我有一个新的Django CMS设置,安装了以下组件(requirements.txt):
Django==1.11
Pillow==5.0.0
psycopg2-binary==2.7.4
django-ckeditor==5.4.0
django-cms==3.5.1
djangocms-text-ckeditor>=3.6.0和以下文件结构:
.
├── main_app
│ ├── admin.py
│ ├── admin.pyc
│ ├── apps.py
│ ├── __init__.py
│ ├── __init__.pyc
│ ├── migrations
│ ├── models.py
│ ├── models.pyc
│ ├── __pycache__
│ ├── tests.py
│ ├── urls.py
│ ├── urls.pyc
│ ├── views.py
│ └── views.pyc
├── project
│ ├── cms_apps.py
│ ├── __init__.py
│ ├── __init__.pyc
│ ├── local_settings.py
│ ├── local_settings.pyc
│ ├── production.py
│ ├── production.pyc
│ ├── __pycache__
│ ├── settings.py
│ ├── settings.pyc
│ ├── static
│ ├── urls.py
│ ├── urls.pyc
│ ├── wsgi.py
│ └── wsgi.pyc
├── templates
│ ├── 404.html
│ ├── base.html
│ └── ...
├── manage.py
└── requirements.txt添加Apphook时,无法在高级页面设置中选择应用程序:

project/cms_apps.py:
from cms.app_base import CMSApp
from cms.apphook_pool import apphook_pool
@apphook_pool.register
class MainApphook(CMSApp):
app_name = 'main_app'
name = 'Main App'
def get_urls(self, page=None, language=None, **kwargs):
return ["main_app.urls"]我在settings.py中安装的应用程序:
INSTALLED_APPS = [
'custom_auth',
'djangocms_admin_style',
'django.contrib.sites',
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'djangocms_text_ckeditor',
'cms',
'menus',
'treebeard',
'sekizai',
'ckeditor',
'main_app',
]我已经根据http://docs.django-cms.org/en/latest/introduction/apphooks.html上的教程重新启动了服务器
请注意,这里没有project/cms_apps.pyc
据我所知,我完全遵循了Apphook教程,那么我错过了什么?
发布于 2018-08-08 00:27:42
好的,所以你需要在你的应用程序中有一个cms_apps.py模块来连接到内容管理系统中。
例如,我有一个名为djangocms_forms的应用程序,它的cms_apps.py如下所示;
class DjangoCMSFormsApphook(CMSApp):
""" Add docs """
name = _('Forms')
urls = ['djangocms_forms.urls']
apphook_pool.register(DjangoCMSFormsApphook)它有以下URL;
urlpatterns = [
url(r'^forms/submit/$', FormSubmission.as_view(),
name='djangocms_forms_submissions'),
url(r'^forms/redirect/$', media_redireect,
name='djangocms_forms_redirect')
]然后,无需任何名称空间(如reverse('djangocms_forms_submissions') )即可访问这些URL
但是,您可以通过向CMSApp添加app_name属性来添加名称空间。例如,我有另一个应用,gallery,它的配置是这样的;
class GalleryApp(CMSApp):
""" Gallery CMS app """
app_name = 'gallery'
name = _("Gallery App")
urls = ["gallery.urls"]然后,此应用程序的URL定义为,{% url "gallery:filterable_gallery_data" %}或在python中定义为reverse('gallery:filterable_gallery_data')
https://stackoverflow.com/questions/51727394
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