第一次尝试使用Django (2.0)模型进行迁移时会导致AttributeError

Question

作为一个完全的初学者，我真的希望我在这里遗漏了一些明显的东西，希望有经验的人可以很容易地指出我的错误。

我正处于创建一些Django模型的第一步，并且不知道如何解决我在尝试进行迁移时遇到的错误。从我的研究来看，这个错误看起来很模糊。我不知道没有属性'model‘是什么意思。

下面是回溯：

Traceback (most recent call last):
File "manage.py", line 22, in <module>
execute_from_command_line(sys.argv)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\__init__.py", line 371, in execute_from_command_line
utility.execute()
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\__init__.py", line 365, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\base.py", line 288, in run_from_argv
self.execute(*args, **cmd_options)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\base.py", line 332, in execute
self.check()
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\base.py", line 364, in check
include_deployment_checks=include_deployment_checks,
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\management\base.py", line 351, in _run_checks
return checks.run_checks(**kwargs)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\core\checks\registry.py", line 73, in run_checks
new_errors = check(app_configs=app_configs)
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\contrib\admin\checks.py", line 22, in check_admin_app
errors.extend(site.check(app_configs))
File "C:\Program Files (x86)\Python36-32\lib\site-packages\django\contrib\admin\sites.py", line 79, in check
if modeladmin.model._meta.app_config in app_configs:
AttributeError: 'Book' object has no attribute 'model'

下面是模型代码：

class Author(models.Model):
    name = models.CharField(max_length=80, blank=False, null=False, unique=True)

class Book(models.Model):
    title = models.CharField(max_length=150)
    description = models.TextField(blank=True, null=True)
    series = models.CharField(max_length=150, blank=True, null=True)
    authors = models.ManyToManyField(Author, blank=True)
    finished = models.BooleanField(default=False, verbose_name="Finished")
    # image = models.ImageField()

    def list_authors(self):
        return ", ".join([author.name for author in self.authors.all()])

class Narrator(models.Model):
    narrator = models.CharField(max_length=80)

class Audiobook(Book):
    length = models.TimeField(blank=False, null=False)
    narrator = models.ForeignKey(Narrator, on_delete=models.SET_NULL, blank=False, null=True)

我已经阅读了一些教程，并阅读了我认为可能相关的任何Django文档，但我仍然遗漏了一些东西。任何想法，或一般的指针将非常感谢。

编辑:添加我的admin.py。我注释掉了所有这些，迁移运行得很好，但在尝试运行另一个迁移时，我仍然发现了相同的错误和类似的错误，但它没有说没有属性'models'，而是说没有属性'urls'

from django.contrib import admin
from .models import (Author, Book, Narrator, Audiobook)

# Register your models here.

admin.site.register(Author, Book)
admin.site.register(Narrator, Audiobook)

Answer 1

尝试逐个注册模型，如下所示：

admin.site.register(Author)
admin.site.register(Narrator)
admin.site.register(Book)
admin.site.register(Audiobook)

Answer 2

通过示例，Django的文档非常容易理解。

您的admin.py必须与以下内容类似：

from django.contrib import admin
from .models import Author, Book, Narrator, Audiobook
class AuthorAdmin(admin.ModelAdmin):
   fields = ['name']
class BookAdmin(admin.ModelAdmin):
   fields = ['title', 'description', ]

# Register your models here.

admin.site.register(Author, Book)
admin.site.register(Narrator, Audiobook)

你可以在这里查看基本的例子来理解tutorial part 7。