如何收集用户输入并提供反馈

Question

我正在努力用我的代码来写一个简单的代码破解游戏。有一个隐藏的代码：

code = ["a","b","b","c"]

我的程序要求用户输入，然后将其存储在一个变量中。我想将用户输入与密码变量进行比较，并给出用户反馈:1表示正确的字母位于正确的位置，0表示正确的字母位于错误的位置，"-“表示错误的字母。

我想出了这样的东西：

feedback = []
input.each_with_index do |v,i|
  if v == code.fetch(i)
    feedback << "1"
  else
    feedback << "-"
  end
end

当它比较相同索引处的元素时，它工作正常。我不知道如何找到代码数组中的元素，但不在同一索引中，并向用户提供反馈。

例如：

code = ["a","b","b","c"]
input = ["b","b","a","z"]
feedback = ["0","1","0","-"]

Answer 1

这段代码适用于你提到的3个例子。

使用2次传递是因为必须在返回0s之前返回1s：

def give_feedback(input, code)
  feedback = Array.new(input.size) { '-' }
  code2 = code.dup

  input.each_with_index do |letter, index|
    if letter == code[index]
      feedback[index] = '1'
      code2[index]    = nil
    end
  end

  input.each_with_index do |letter, index|
    next if feedback[index] == '1'
    found = code2.index(letter)
    if found
      feedback[index]  = '0'
      code2[found]     = nil
    end
  end
  feedback
end

p give_feedback(%w(b b a z), %w(a b b c))
# ["0", "1", "0", "-"]
p give_feedback(%w(a a a a), %w(a b b c))
# ["1", "-", "-", "-"]
p give_feedback(%w(c c b a), %w(a b b c))
# ["0", "-", "1", "0"]

Answer 2

可以使用include?方法查看该字符是否在列表中的不同索引处。如下所示：

input.each_with_index do |v,i|
  if v == code.fetch(i)
    feedback << "1"
  elsif code.include?(v)
    # right character, wrong spot
    feedback << "0"
  else
    feedback << "-"
  end
end

Answer 3

另一个解决方案

code = ["a","b","b","c"]
input = ["b","b","a","z"]

feedback = input.map.with_index do |num, ind|
  if code.include? num
    code[ind] == num ? '1' : '0'
  else
    '-'
  end
end

=> ['0', '1', '0', '-']

如果您想在前面定义feedback，只需将第一个变体编辑为：

code = ["a","b","b","c"]
input = ["b","b","a","z"]
feedback = []

input.each_with_index do |num, ind|
  if code.include? num
    feedback << (code[ind] == num ? '1' : '0')
  else
    feedback << '-'
  end
end

结果会是一样的