如何使用列表分隔文本？

Question

这是我的代码，但是当我想让它计算句子中的字符时，它一直将答案作为一个输出。

#-----------------------------
myList = []
characterCount = 0
#-----------------------------

Sentence = "hello world"
newSentence = Sentence.split(",")
myList.append(newSentence)
print(myList)
for character in myList:
    characterCount += 1
print (characterCount)

谢谢你的帮助

Answer 1

使用单行解决方案

len(list("hello world"))  # output 11

或者..。

*快速修复您的原始代码

修改后的代码：

#-----------------------------
myList = []
characterCount = 0
#-----------------------------

Sentence = "hello world"
myList = list(Sentence)
print(myList)
for character in myList:
    characterCount += 1
print (characterCount)

输出：

['h', 'e', 'l', 'l', 'o', ' ', 'w', 'o', 'r', 'l', 'd']
11

Answer 2

您可以循环遍历句子，并以这种方式计算字符：

#-----------------------------
myList = []
characterCount = 0
#-----------------------------

Sentence = "hello world"

for character in Sentence:
    characterCount += 1

print(characterCount)

Answer 3

基本上你犯了几个错误:拆分分隔符应该是‘’而不是'，'，不需要创建一个新的列表，并且你是在单词而不是字符上循环。

代码应如下所示：

myList = []
characterCount = 0
#-----------------------------

Sentence = "hello world"
newSentence = Sentence.split(" ")

for words in newSentence:
    characterCount += len(words)

print (characterCount)