我有这样的疑问:
SELECT U.LOCATION,SUM(S.EXISTENCIA) AS Total
FROM LOCATIONS U
LEFT JOIN CANT_WAREHOUSE S ON U.LOCATION= S.LOCATION
WHERE U.ENABLED= 1
GROUP BY U.LOCATION并像这样返回数据:
LOCATION | Total
2A-1 | 566.0000000
2A-2 | 14.0000000
2A-3 | 1.0000000
2A-4 | (null)
2A-5 | 1.0000000
2A-6 | (null)
2A-7 | 6.0000000
2B-1 | 560.0000000
2B-2 | (null)有没有办法使用子查询或类似的方法来获取'LOCATION‘,其中'TOTAL’= null?
发布于 2017-01-31 00:05:29
使用HAVING子句
SELECT U.LOCATION,SUM(S.EXISTENCIA) AS Total
FROM LOCATIONS U
LEFT JOIN CANT_WAREHOUSE S ON U.LOCATION= S.LOCATION
and U.ENABLED= 1
GROUP BY U.LOCATION
HAVING SUM(S.EXISTENCIA) IS NULL发布于 2017-01-31 00:05:29
使用NOT EXISTS
SELECT U.LOCATION,
NULL AS Total
FROM LOCATIONS U
WHERE NOT EXISTS (SELECT 1
FROM CANT_WAREHOUSE S
WHERE U.LOCATION = S.LOCATION)
AND U.ENABLED = 1
GROUP BY U.LOCATION https://stackoverflow.com/questions/41940278
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