首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >jsgrid入门示例不起作用

jsgrid入门示例不起作用
EN

Stack Overflow用户
提问于 2018-08-07 23:49:12
回答 1查看 548关注 0票数 1

对于我的一个项目,我必须使用jsgrid (http://js-grid.com)。

为了测试如何使用jsgrid,我想做一个“入门”示例(http://js-grid.com/getting-started。我的问题是,在我看来,我按照示例所说的做了所有的事情,但它最终并不起作用。

我遗漏了什么?

下面是我的代码:

代码语言:javascript
复制
<!DOCTYPE html>
<html>
<head>
    <link type="text/css" rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.css" />
    <link type="text/css" rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid-theme.min.css" />
    
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
    <script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.js"></script>
    <script>
        var clients = [
            { "Name": "Otto Clay", "Age": 25, "Country": 1, "Address": "Ap #897-1459 Quam Avenue", "Married": false },
            { "Name": "Connor Johnston", "Age": 45, "Country": 2, "Address": "Ap #370-4647 Dis Av.", "Married": true },
            { "Name": "Lacey Hess", "Age": 29, "Country": 3, "Address": "Ap #365-8835 Integer St.", "Married": false },
            { "Name": "Timothy Henson", "Age": 56, "Country": 1, "Address": "911-5143 Luctus Ave", "Married": true },
            { "Name": "Ramona Benton", "Age": 32, "Country": 3, "Address": "Ap #614-689 Vehicula Street", "Married": false }
        ];
     
        var countries = [
            { Name: "", Id: 0 },
            { Name: "United States", Id: 1 },
            { Name: "Canada", Id: 2 },
            { Name: "United Kingdom", Id: 3 }
        ];
     
        $("#jsGrid").jsGrid({
            width: "100%",
            height: "400px",
     
            inserting: true,
            editing: true,
            sorting: true,
            paging: true,
     
            data: clients,
     
            fields: [
                { name: "Name", type: "text", width: 150, validate: "required" },
                { name: "Age", type: "number", width: 50 },
                { name: "Address", type: "text", width: 200 },
                { name: "Country", type: "select", items: countries, valueField: "Id", textField: "Name" },
                { name: "Married", type: "checkbox", title: "Is Married", sorting: false },
                { type: "control" }
            ]
        });
    </script>
</head>
<body>
    <div id="jsGrid"></div>
</body>
</html>

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2018-08-09 17:47:35

您的脚本代码在DOM准备好之前运行。我把你的脚本包在中间:

代码语言:javascript
复制
$(document).ready(function() {

和:

代码语言:javascript
复制
});

它与所显示的表格运行得很好。有关说明,请参阅here

jsGrid是一个很棒的工具。不幸的是,它的诊断几乎为零。有些地方可能会出错,比如一个简单的打字错误,但根本没有任何迹象表明哪里出了错。

票数 2
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/51730839

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档