如何获得Javascript BigInt除法的有效位和指数结果

Question

我想将两个BigInt数相除，得到一些有效数字和一个指数。到目前为止，我得到了这样的结论：

f = (numerator, denominator, significantsLength) => {
      const denominatorLength = ('' + denominator).length
      const extension = significantsLength + denominatorLength
      const extendedNumerator = numerator * 10n ** BigInt(extension)
      const div = extendedNumerator / denominator
      const divLength = ('' + div).length
      const digitsSurplus = divLength - significantsLength
      const significants = div / 10n ** BigInt(digitsSurplus)
      const exponent = digitsSurplus - extension
      return significants + 'e' + exponent
    }

因此，f(1n,3n,3)结果为'333e-3'

还能更好吗？此代码不四舍五入。对于零和负数，它也不能很好地工作。

Answer 1

您可以使用Basenumber.js在两个BigIntegers之间进行除法，然后用具有n有效数字的指数来表示它：

在这里试试吧

​

// Number of decimals needed
Base.setDecimals(100);

let x = Base('555555555555555555555555555555555555555555555555555');
let y = Base('999999999999999999999999999999999999999999999999');

let z = x.divide(y);

console.log( z.toString() );
console.log( z.toExponential(4) );

<script src='https://cdn.jsdelivr.net/gh/AlexSp3/Basenumber.js@main/BaseNumber.min.js'></script>

​

负数

​

// Number of decimals needed
Base.setDecimals(100);

let x = Base('-1e+1000');
let y = Base(9);

let z = x.divide(y);

console.log( z.toString() );
console.log( z.toExponential(10) );

 <script src='https://cdn.jsdelivr.net/gh/AlexSp3/Basenumber.js@main/BaseNumber.min.js'></script>

​