Javascript声称是一种函数式语言,但感觉上肯定不是。它缺少让函数式语言变得整洁的大多数东西,其中之一就是点自由风格。幸运的是,我们在ES6中得到了箭头函数和代理,所以我自己用代理实现了无点风格:
let pfree = ctx => f => new Proxy (f, {
has: (t, p) => p in t || p in ctx
, get: (t, p) => {
let k = p in t? t[p]: ctx[p];
if (k instanceof Function) return (
function fetch (_k) {
return pfree (ctx) ( x => ( q => q instanceof Function
? fetch (q)
: t (q)
) ( _k(x) )
)
})(k);
return k;
}
});相当令人头疼,但它做了这项工作-在nodejs中,你可以这样使用它:
let p = pfree (global) (x => x)
with (p) {
add = x => y => x + y
succ = add (1)
five = succ . add (2) . succ (1)
}
console.log(five) // 5当你创建更高阶的函数时,问题就出现了:
with (p) {
flip = f => x => y => f (y) (x)
Const = a => b => a
dot = f => a => b => f(a(b))
ap = f => g => x => f (x) (g (x))
zero = flip (Const)
succ = ap (dot)
num = n => n (x => x + 1) (0) // The number n is represented by running a function n times over some input
console.log ( num ( succ ( succ ( succ (zero) )))) // 3
console.log ( num . succ . succ . succ (zero) ) // [Function]
}我真的不明白为什么..
想法?
发布于 2016-08-22 09:21:46
问题很简单:
succ . add(2)与无法区分
(succ . add) (2)使用JavaScript属性访问的规则,但您希望它们做不同的事情。
解决方案是不可能的(我敢说),但您可以通过引入自定义分组运算符来解决问题:
group(succ . add) (2)您还应该在分配给p的属性时调用它。您应该能够完成以下工作:
addFour = succ . add (2) . succ
five = group(succ . add (2) . succ) (1)
fiveAgain = addFour (1)
console.log ( group(num . succ . succ . succ) (zero) ) // 3https://stackoverflow.com/questions/39070152
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