将文件行与python中的字符串进行比较，以及不一致

Question

这段代码应该按照执行顺序做一些重要的事情：

1.打开并读取文件"Goods“

2.将文件"Goods“中的任意一行分配给字典"goods”

3.遍历if块，该代码块将为字典"cost“分配一个随机值，前提是goodsx等于要比较的字符串。

4.打印“货物”和“成本”

5.重复步骤2-4，再重复2次。

from random import randint

print("You search for things to buy in the market, and find:")
f = open('Goods', 'r') #Opens file "Goods"
lines = f.readlines() #Loads all lines from "Goods"
goods = {1:"", 2:"", 3:""}
cost = {1:"", 2:"", 3:""}
x = 0
while x < 3:
    x += 1
    goods[x] = lines[randint(0, 41)].strip()

#Checks to see if goods[x] is equal to the string on the right, if it is, it assigns cost[x] to a random integer
    if goods[x] == "Lumber":
        cost[x] = randint(2, 3)
    elif goods[x] == "Rum":
        cost[x] == randint(3, 4)
    elif goods[x] == "Spices":
        cost[x] = randint(4, 5)
    elif goods[x] == "Fruit":
        cost[x] == randint(2, 4)
    elif goods[x] == "Opium":
        cost[x] == randint(1, 5)


    findings = '%s for %s gold.' %(goods[x], cost[x])
    print(findings)

这段代码的问题是，当goodsx等于: Rum、Fruit或Opium时，字典：“cost”不能从if块中获得赋值。

有人能告诉我这是怎么回事吗？

The file "Goods"

Answer 1

你的问题是你使用的是两个等号。cost[x] == randint(3, 4)你只需要使用一个。希望这能有所帮助！