使用不同的变量以相同的速度遍历循环

Question

我正在尝试弄清楚如何同时迭代一个循环。我不确定我的问题措辞是否正确。

例如，我需要将来自两个数据帧的列1的差值存储在df的Calibrated Power 0 [dBm]或列4中。我需要将列2存储在Calibrated Power 10 [dBm]列中。目前，正在将相同的数据复制到df的第4-6列

attenuator_power = [0, 10, 30]
for i in range(1, 3):
    ydata_sans_att = df_sans_attenuator.iloc[:, i]
    ydata_df = df.iloc[:, i]
    for j in attenuator_power:
        df['Calibrated Power {} [dBm]'.format(j)] = ydata_df - ydata_sans_att

Answer 1

下面是如何对它们进行配对：

for i, j in zip(range(1,3), attenuator_power):
    ydata_sans_att = df_sans_attenuator.iloc[:, i]
    ydata_df = df.iloc[:, i]
    df['Calibrated Power {} [dBm]'.format(j)] = ydata_df - ydata_sans_att  

Answer 2

@mauve已经给出了一个很好的答案，但这里有另一个选择：

for i, j in enumerate(attenuator_power, 1):
    ydata_sans_att = df_sans_attenuator.iloc[:, i]
    ydata_df = df.iloc[:, i]
    df['Calibrated Power {} [dBm]'.format(j)] = ydata_df - ydata_sans_att