我正在使用conductor,并且我想在其中初始化GoogleApiClient。正如conductor文档中所述,导体是用来替换Fragment的。在Fragment中,我可以很容易地获得一个activity。在conductor中有什么方法可以做到这一点吗
class SignInController : Controller(), GoogleApiClient.OnConnectionFailedListener {
private lateinit var mGoogleApiClient: GoogleApiClient
private lateinit var mFirebaseAuth: FirebaseAuth
override fun onCreateView(inflater: LayoutInflater, container: ViewGroup): View {
val view = inflater.inflate(R.layout.controller_sign_in, container, false)
val gso = GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
.requestIdToken(view.context.getString(R.string.default_web_client_id))
.requestEmail()
.build()
mGoogleApiClient = GoogleApiClient.Builder(view.context)
.enableAutoManage(view.context /* I need an activity here */, this /* OnConnectionFailedListener */)
.addApi(Auth.GOOGLE_SIGN_IN_API, gso)
.build()
mFirebaseAuth = FirebaseAuth.getInstance()
return view
}
}我尝试使用view.context而不是activity,但它不起作用。它只需要FragmentActivty。如何在conductor内部初始化GoogleApiClient或将其传递到conductor?我不想在这里使用DI。
发布于 2018-01-31 04:03:15
我找到了这个问题的解决方案:非常简单。view.context已经是MyActivity了,我只需要对它进行转换:
GoogleApiClient.Builder(view.context).enableAutoManage(view.context as MyActivity, this)您还可以通过在controller中调用getActivity()来获取父activity
https://stackoverflow.com/questions/48526008
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