我正在尝试使用XML文件上的XSLT将其转换为另一个XML文件。这是我的XSLT
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:og="http://og.com"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:fn="http://www.w3.org/2005/xpath-functions"
exclude-result-prefixes="xs fn">
<xsl:output method="xml" encoding="UTF-8" byte-order-mark="no"
indent="yes" />
<xsl:template match="@*|node()">
<xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
</xsl:template>
<xsl:template match="_source/extension">
<xsl:for-each select="*">
<xsl:element name="MT">
<xsl:attribute name="N" select="name()"/>
<xsl:attribute name="V" select="."/>
</xsl:element>
</xsl:for-each>
</xsl:template>
<xsl:template match="/">
<GSP>
<xsl:attribute name="VER">
<xsl:value-of select="3.2" />
</xsl:attribute>
<xsl:for-each select="root">
<TM>
<xsl:value-of select="(floor(took) div floor(1000))" />
</TM>
<RES>
<M>
<xsl:value-of select="floor(hits/total)" />
</M>
<xsl:for-each select="hits/hits">
<xsl:variable name="var1_resultof_first" as="node()"
select="_source" />
<R>
<xsl:attribute name="N">
<xsl:number format="0" level="single" />
</xsl:attribute>
<U>
<xsl:sequence
select="xs:string(xs:anyURI(fn:string($var1_resultof_first/U)))" />
</U>
<UE>
<xsl:sequence
select="xs:string(xs:anyURI(fn:string($var1_resultof_first/UE)))" />
</UE>
<UD>
<xsl:sequence
select="xs:string(xs:anyURI(fn:string($var1_resultof_first/UD)))" />
</UD>
<T>
<xsl:sequence select="fn:string($var1_resultof_first/T)" />
</T>
<Last-Modified>
<xsl:value-of select="substring-before(_source/submitTime,'T')" />
</Last-Modified>
<S>
<xsl:for-each select="highlight/newContent">
<xsl:sequence select="fn:string(.)" />
</xsl:for-each>
</S>
</R>
</xsl:for-each>
</RES>
</xsl:for-each>
</GSP>
</xsl:template>
</xsl:stylesheet>它有两个匹配到的template.One
<xsl:template match="_source/extension">和另一个匹配
<xsl:template match="/">但是,当我对我的输入XML运行这个XSLT时,只有上面的模板被附加到我的XML上
<xsl:template match="/">不应用另一个匹配项(_source/match)。我们可以在同一个XSLT中使用多个模板吗?我可能漏掉了什么。
发布于 2016-08-23 02:55:35
当然,只有match="/"模板应用于您的XML。它匹配根节点,并且从不调用任何其他模板,因此没有调用任何其他模板的事实应该不会让人感到惊讶。
为了获得更好的结果,请删除代码中的每个<xsl:for-each>,并将其替换为<xsl:apply-templates>和适当的匹配模板。<xsl:for-each>有其用法,但在您的用例中没有一种用法。
如下所示:
<xsl:template match="/">
<GSP VER="3.2">
<xsl:apply-templates match="root" />
</GSP>
<xsl:template>
<xsl:template match="root">
<TM>
<!-- floor(1000) is... 1000. Maybe you mean something else? -->
<xsl:value-of select="floor(took) div floor(1000)" />
</TM>
<RES>
<M><xsl:value-of select="floor(hits/total)" /></M>
<xsl:apply-templates="hits/hits" />
</RES>
</xsl:template>
<xsl:template match="hits/hits">
<R>
<xsl:attribute name="N">
<xsl:number format="0" level="single" />
</xsl:attribute>
<!-- you could use select="_source/U,_source/UE,_source/UT" here, too -->
<xsl:apply-templates select="_source/U" mode="URI" />
<xsl:apply-templates select="_source/UE" mode="URI" />
<xsl:apply-templates select="_source/UD" mode="URI" />
<T><xsl:value-of select="_source/T" /></T>
<Last-Modified>
<xsl:value-of select="substring-before(_source/submitTime,'T')" />
</Last-Modified>
<xsl:apply-templates select="highlight/newContent" />
</R>
</xsl:template>
<xsl:template match="*" mode="URI">
<xsl:copy>
<xsl:value-of select="xs:anyURI(.)" />
</xsl:copy>
</xsl:template>
<xsl:template match="highlight/newContent">
<S><xsl:value-of select="." /></S>
</xsl:template>目标是做一件事的简短的、有重点的模板。
使用<xsl:apply-templates>在正确的位置调用您的_source/extension模板。也从该模板中删除<xsl:for-each>。
有关模板如何在What are the differences between 'call-template' and 'apply-templates' in XSL?中工作的更多详细信息,请阅读For loops vs. apply-templates和differences between for-each and templates in xsl?以及其他类似的文章。
https://stackoverflow.com/questions/39086391
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