Xlsxwriter Python3错误

Question

在关闭xlsxwriter时，我的python3脚本遇到了问题。我已经包含了workbook.close()，但这似乎导致了某种错误。有人知道问题出在哪里吗？

import xlsxwriter
import statistics

workbook = xlsxwriter.Workbook('data.xlsx')
worksheet = workbook.add_worksheet()
bold = workbook.add_format({'bold': True})

power = []

for row in list:
    power.append(row)
    worksheet.write(i, col, row)
    col += 1

worksheet.write(i, col, statistics.median(power))

workbook.close()

Traceback (most recent call last):
  File "example.py", line 71, in <module>
    workbook.close()
  File "/usr/local/lib/python3.4/dist-packages/xlsxwriter/workbook.py", line 311, in close
    self._store_workbook()
  File "/usr/local/lib/python3.4/dist-packages/xlsxwriter/workbook.py", line 619, in _store_workbook
    xml_files = packager._create_package()
  File "/usr/local/lib/python3.4/dist-packages/xlsxwriter/packager.py", line 139, in _create_package
    self._write_shared_strings_file()
  File "/usr/local/lib/python3.4/dist-packages/xlsxwriter/packager.py", line 286, in _write_shared_strings_file
    sst._assemble_xml_file()
  File "/usr/local/lib/python3.4/dist-packages/xlsxwriter/sharedstrings.py", line 54, in _assemble_xml_file
    self._write_sst_strings()
  File "/usr/local/lib/python3.4/dist-packages/xlsxwriter/sharedstrings.py", line 84, in _write_sst_strings
    self._write_si(string)
  File "/usr/local/lib/python3.4/dist-packages/xlsxwriter/sharedstrings.py", line 96, in _write_si
    string = re.sub('(_x[0-9a-fA-F]{4}_)', r'_x005F\1', string)
  File "/usr/lib/python3.4/re.py", line 179, in sub
    return _compile(pattern, flags).sub(repl, string, count)
TypeError: can't use a string pattern on a bytes-like object

Answer 1

我在示例中添加了一些变量初始化来编译它，它似乎可以在Python 2和3上正确运行：

import xlsxwriter
import statistics

workbook = xlsxwriter.Workbook('data.xlsx')
worksheet = workbook.add_worksheet()
bold = workbook.add_format({'bold': True})

power = []

# I added these variables to the OP program.
list = [1, 2, 3, 4, 5]
i = 0
col = 0

for row in list:
    power.append(row)
    worksheet.write(i, col, row)
    col += 1

worksheet.write(i, col, statistics.median(power))

workbook.close()

输出：

​

​

我猜这和你的例子的区别在于列表数组的内容。

你能用一个演示实际问题的例子来更新你的问题吗？

Answer 2

您需要使用.decode将类似字节的对象转换为字符串，例如obj = response.read().decode('utf-8').

在你的例子中，列表中的对象必须是字节类型，将它们转换为字符串。

请参阅Convert bytes to a Python String