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社区首页 >问答首页 >顺序异步任务队列不会等到异步任务结束

顺序异步任务队列不会等到异步任务结束
EN

Stack Overflow用户
提问于 2016-09-01 23:09:30
回答 2查看 71关注 0票数 1

我尝试按顺序对异步任务进行排队,因此我为此创建了一个类:

代码语言:javascript
复制
 public class TaskSequentialQueue : IDisposable, ITaskSequentialQueue
    {
        public delegate void OnExeptionDelegate(Exception ex);

        private readonly Queue<Task> m_queue = new Queue<Task>();
        private readonly Object m_lock = new Object();
        private readonly CancellationTokenSource m_CancelToken = new CancellationTokenSource();
        private readonly OnExeptionDelegate m_onExeptionDelegate = null;
        private Task m_currentTask = null;
        private bool m_isDisposed = false;      

        public TaskSequentialQueue(OnExeptionDelegate expDelegate = null)
        {
            m_onExeptionDelegate = expDelegate;
        }

        public void Dispose()
        {
            Dispose(true);
            GC.SuppressFinalize(this);
        }

        protected virtual void Dispose(bool isDisposing)
        {
            if (m_isDisposed)
            {
                return;
            }

            if (isDisposing)
            {
                lock (m_lock)
                {
                    m_isDisposed = true;
                    m_queue.Clear();
                }

                m_CancelToken.Cancel();
                m_CancelToken.Dispose();
            }
        }

        public void EnqueueTask( Task task)
        {
            lock (m_lock)
            {
                if (m_isDisposed)
                    throw new ObjectDisposedException("TaskSequentialQueue");

                m_queue.Enqueue(task);
            }

            StartNextTask();
        }

        public void EnqueueTask( Func<Task> task)
        {
            EnqueueTask(new Task<Task>(task));
        }

        public Task EnqueueTaskAndWait( Task task)
        {
            TaskCompletionSource<int> taskSource = new TaskCompletionSource<int>();
            lock (m_lock)
            {
                if (m_isDisposed)
                    throw new ObjectDisposedException("TaskSequentialQueue");

                Func<Task> toDo = async () =>
                {                                        
                    var waitabletask = task.ContinueWith( antecedent => 
                                                            { 
                                                                taskSource.SetResult(0); 
                                                                if (antecedent.Exception != null)
                                                                    throw antecedent.Exception; 
                                                            });
                    task.Start();
                    await waitabletask;
                };
                this.EnqueueTask(toDo);
            }

            StartNextTask();

            return taskSource.Task;  //TODO! propagate the exception correctly ?
        }

        private void StartNextTask()
        {
            Task theTask = null;
            lock(m_lock)
            {
                if (m_currentTask == null && m_queue.Count > 0 && !m_isDisposed)
                {
                    m_currentTask = m_queue.Dequeue();
                    theTask = m_currentTask;
                }
            }      
            if (theTask != null)
            {
                theTask.Start();  
                theTask.ContinueWith( (antecedent) =>
                    {
                        Exception theEx = antecedent.Exception;
                        if (theEx == null && antecedent is Task<Task>)
                            theEx = (antecedent as Task<Task>)?.Result.Exception;

                        if (m_onExeptionDelegate != null && theEx != null)
                        {
                            try { m_onExeptionDelegate(theEx); } catch(Exception) {}
                        }

                        lock(m_lock)
                        {
                            m_currentTask = null;
                        }

                        Task.Run( () =>  StartNextTask() );
                }
            }
        }
    }

我是这样使用它的:

代码语言:javascript
复制
     Func<Task> action = async () =>
                {
                   Log("Entered");
                   await Task.Delay(5000);
                   Log("Exited");
                }

m_taskSequentialQueue.EnqueueTask( action );
m_taskSequentialQueue.EnqueueTask( action );

我希望我的日志是:

代码语言:javascript
复制
Entered
Exited
Entered
Exited

相反,我得到的是:

代码语言:javascript
复制
Entered
Entered
Exited
Exited

我不确定我做错了什么。

谢谢

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2016-09-01 23:29:50

当您在StartNextTask中执行theTask.ContinueWith(时,您继续执行的是内部任务的开始,而不是内部任务的完成。一旦内部任务命中第一个awaittheTask任务就会被认为是完成的,因为返回的是函数。

作为创可贴,你可以这样做

代码语言:javascript
复制
if (theTask != null)
{
    theTask.Start();  
    if(theTask is Task<Task>)
    {
       theTask = ((Task<Task>)theTask).Unwrap();
    }
    theTask.ContinueWith(...

然而,我认为你使用“冷任务”的整个方法是有缺陷的。您应该只使用Queue<Func<Task>>而不是Queue<Task>,这将使您的代码变得更简单。

票数 4
EN

Stack Overflow用户

发布于 2016-09-01 23:31:43

代码语言:javascript
复制
        Func<Task> action = async () =>
        {
            lock (lock_x)
            {
                Console.WriteLine("Entered");
                Thread.Sleep(5000);
                Console.WriteLine("Exited");
            }
        };

应该可以工作,因为您的队列实现是按顺序提交它们的。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/39275185

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