如何排除"node_modules“

Question

如何从运行中排除node_modules？

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我以为webpack-node-externals就是用来完成这项任务的。这是我的webpack.test-config.js

const nodeExternals = require('webpack-node-externals');
const config = {};

// in order to ignore built-in modules like path, fs, etc.
config.target = 'node';

// in order to ignore all modules in node_modules folder
config.externals = [nodeExternals()];

config.output = {
    // sourcemap support for IntelliJ/Webstorm
    devtoolModuleFilenameTemplate: '[absolute-resource-path]',
    devtoolFallbackModuleFilenameTemplate: '[absolute-resource-path]?[hash]'
};

// 'cheap-module-source-map' faster than 'source-map'
config.devtool = "source-map";


module.exports = config;

我从package.json运行测试

"test": "mocha-webpack --webpack-config webpack.config-test.js \"**/test/*.test.js\"",

Answer 1

添加以下代码并查看注释以了解详细信息。详情请参阅此链接：https://www.npmjs.com/package/webpack-node-externals

var nodeExternals = require('webpack-node-externals');
...
module.exports = {
...
target: 'node', // in order to ignore built-in modules like path, fs,     etc. 
externals: [nodeExternals()], // in order to ignore all modules in   node_modules folder 
...
};