我已经在网上找遍了,但是找不到一个awnser来解决我的错误,我正在为php mysql做一个简单的更新表单,它就是不更新它。
请参阅下面的代码
表格:
<form class="" action="edit_account.php" method="post">
<input type="text" name="username" placeholder="username" value="<?php echo $r['username']; ?>">
<input type="text" name="name" placeholder="username" value="<?php echo $r['name']; ?>">
<input type="text" name="email" placeholder="username" value="<?php echo $r['email']; ?>">
<input type="text" name="country" placeholder="username" value="<?php echo $r['country']; ?>">
<input type="submit" value="Edit" name="submit">
</form>edit_account.php
session_start();
include("db_config.php");
include("../templates/sitehead.php");
$query = $connect->query("SELECT * FROM `users` WHERE `email` = '". $_SESSION['email'] ."'");
$r = $query->fetch_assoc();
$profile = $connect->query("SELECT * FROM `users.profiles` WHERE `user_id` = '". $r['id'] ."'");
$p = $profile->fetch_assoc();
if(isset($_GET['do']) == "submit") {
$username = clean($connect, $_POST['username']);
$connect->query("UPDATE `users.profiles` SET `username` = '". $username ."' WHERE `user_id` = '". $r['id'] ."'");
}
$query = $connect->query("SELECT * FROM `users.profiles` WHERE `id` = '". $r['id'] ."'");
$p = $query->fetch_assoc();发布于 2016-08-27 08:04:13
您应该使用以下语句:
if(isset($_POST['submit']) && $_POST['submit'] == "Edit") {
}https://stackoverflow.com/questions/39176092
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