我使用Nginx作为web主机和代理,在同一个设备上运行的websocket监听端口8888。尝试找到一种让nginx监听80并将websocket请求转发到内部端口的方法。而不会将新端口暴露在外部。这有可能吗?
更新:
这是我当前的配置:
error_log /var/log/nginx/error_log.log warn;
map $http_upgrade $connection_upgrade {
default upgrade;
'' close;
}
upstream websocket {
server localhost:8888;
}
server {
listen 80;
#listen [::]:80 default_server;
# SSL configuration
#
# listen 443 ssl default_server;
# listen [::]:443 ssl default_server;
#
# Self signed certs generated by the ssl-cert package
# Don't use them in a production server!
#
# include snippets/snakeoil.conf;
root /var/www/html/EncoderAdmin;
# Add index.php to the list if you are using PHP
index index.php index.html index.htm index.nginx-debian.html;
server_name _;
location / {
# First attempt to serve request as file, then
# as directory, then fall back to displaying a 404.
try_files $uri $uri/ =404;
auth_basic "Restricted Content";
auth_basic_user_file /etc/nginx/.htpasswd;
}
location /ws {
proxy_pass http://localhost:8888;
proxy_http_version 1.1;
proxy_set_header Host $http_host;
proxy_set_header X-Real-IP $remote_addr;
proxy_set_header Upgrade $http_upgrade;
proxy_set_header Connection "upgrade";
}
}当我尝试使用ws://address/ws连接到它时,我得到:
与'ws://address/ws‘的WebSocket连接失败:在WebSocket握手期间出错:意外响应代码: 400
发布于 2017-02-28 02:35:08
是的,假设你能区分普通的HTTP请求和套接字请求,这是可能的。
最简单的解决方案是将套接字uri与location匹配,例如,所有对/ws的请求都将被重定向到localhost:8888,任何其他url都会被重定向到localhost:8889。下面是一个配置示例
server {
server_name _;
location /ws {
proxy_pass http://localhost:8888;
# this magic is needed for WebSocket
proxy_http_version 1.1;
proxy_set_header Upgrade $http_upgrade;
proxy_set_header Connection "upgrade";
proxy_set_header Host $http_host;
proxy_set_header X-Real-IP $remote_addr;
}
location / {
proxy_pass http://localhost:8889;
}
}您还应该记得将websocket服务器绑定到localhost:8888,而不是绑定到0.0.0.0:8888。这一步是不需要的,但是有了它,原来的端口就不会暴露了!
https://stackoverflow.com/questions/42491668
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