我正在使用Vinyl-ftp来做部署,当我尝试连接FileZilla或总指挥官时,一切正常,但当我尝试使用Gulp任务时,我得到了奇怪的错误,我看不到区别,这是我的Gulp任务和错误信息
gulp.task('ftp-test-connection', function () {
var conn = ftp.create({
host: 'hostname',
user: 'user',
password: 'password',
parallel: 10,
log: gutil.log
});
var globs = [
'./styles/**/*{css,png,jpg,gif,ttf,woff,eof,svg,woff2}',
'./images/**',
'./views/**',
'./scripts/vendor.scripts.min.js',
'./dist/index.html',
'./dist_test/main.scripts.min.js',
'./dist_test/web.config'
];
return gulp.src(globs, { base: '.', buffer: false })
.pipe(gulpIf('dist/index.html', rename({ dirname: '' })))
.pipe(gulpIf('dist/web.config', rename({ dirname: '' })))
.pipe(gulpIf('dist_test/main.scripts.min.js', rename({ dirname: '/scripts' })))
.pipe(conn.newer('/site/wwwroot'))
.pipe(conn.dest('/site/wwwroot'));
});这是我的错误**
[11:31:59] ERROR Error: User cannot log in.
at makeError (C:\node_modules\vinyl-ftp\node_modules\ftp\lib\connection.js:1067:13)
at Parser.<anonymous> (C:\node_modules\vinyl-ftp\node_modules\ftp\lib\connection.js:113:25)
at emitTwo (events.js:87:13)
at Parser.emit (events.js:172:7)
at Parser._write (C:\node_modules\vinyl-ftp\node_modules\ftp\lib\parser.js:59:10)
at doWrite (_stream_writable.js:292:12)
at writeOrBuffer (_stream_writable.js:278:5)
at Parser.Writable.write (_stream_writable.js:207:11)
at Socket.ondata (C:\node_modules\vinyl-ftp\node_modules\ftp\lib\connection.js:273:20)
at emitOne (events.js:77:13)
at Socket.emit (events.js:169:7)
at readableAddChunk (_stream_readable.js:146:16)
at Socket.Readable.push (_stream_readable.js:110:10)
at TCP.onread (net.js:523:20) (530)
Process terminated with code 1.**
发布于 2016-10-18 19:12:05
我在“黑胶”和Azure App Services (也就是Azure网站)。
在我的例子中,这个问题是由Azure FTP用户名中包含的"\“字符引起的。我只需要将"\“加倍(例如:”某用户\$某用户“)来解决这个问题。
我希望这会有帮助..。
M.
https://stackoverflow.com/questions/39246337
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