JsonResponse选项参数

Question

在控制器中，我有：

return response()->json(
    [
        'number' => (float)8
    ],
    Response::HTTP_OK,
    [],
    JSON_PRESERVE_ZERO_FRACTION
);

这是输出：

{
    "number": 8
}

有没有可能得到8.0？这样做效果很好：

json_encode(['number' => (float)8],JSON_PRESERVE_ZERO_FRACTION);

更新:当我将上面的response()->json设置为$variable，然后设置为print_r($variable)时，我得到的结果是：

(所以它看起来像是在工作，但在浏览器中返回时，我仍然得到8而不是8.0)

Illuminate\Http\JsonResponse Object
(
    [data:protected] => {"number":8.0}
    [callback:protected] => 
    [encodingOptions:protected] => 1024
    [headers] => Symfony\Component\HttpFoundation\ResponseHeaderBag Object
        (
            [computedCacheControl:protected] => Array
                (
                    [no-cache] => 1
                    [private] => 1
                )

            [cookies:protected] => Array
                (
                )

            [headerNames:protected] => Array
                (
                    [cache-control] => Cache-Control
                    [date] => Date
                    [content-type] => Content-Type
                )

            [headers:protected] => Array
                (
                    [cache-control] => Array
                        (
                            [0] => no-cache, private
                        )

                    [date] => Array
                        (
                            [0] => Thu, 08 Feb 2018 11:27:34 GMT
                        )

                    [content-type] => Array
                        (
                            [0] => application/json
                        )

                )

            [cacheControl:protected] => Array
                (
                )

        )

    [content:protected] => {"number":8.0}
    [version:protected] => 1.0
    [statusCode:protected] => 200
    [statusText:protected] => OK
    [charset:protected] => 
    [original] => Array
        (
            [number] => 8
        )

    [exception] => 
)

Answer 1

使用number_format()

json_encode(['number' => number_format(8, 1)]);

如果数字以字符串形式出现，请使用(float)$stringNumber而不是$stringNumber