将文本转换为数组- Swift

Question

为了好玩，我正在帮助我的学校创建一个应用程序，它有所有的课程取消供学生使用。从我的IT技术人员那里，我得到了一个相当复杂的结构，其中包含类名、教师和其他信息，如下所示：

 3818,"20170217",5,752,64,"Rh",,"fr_2",,,,"iV5",,,"IS10a~IS10b~IS10c~IS10d","Z",,1,"IS10a~IS10b~IS10c~IS10d",C,201702161517,"-"

 3819,"20170217",6,752,102,"Rh",,"fr",,,,"iB3","iB3",,"IT10a","Z",,0,"IT10a",,201702161517,"-"

 3820,"20170217",8,752,119,"Rh",,"fr",,,,"iC1.2","iC1.2",,"IS6a","Z",,0,"IS6a",,201702161517,"-"

 3821,"20170227",2,753,207,"Dd","Kru","sc",,,,"iB8","iB8",,"IS9b","Z",,2097152,"IS9b",,201702270804,"+~-"

 3822,"20170227",3,753,8,"Dd",,"phH_1",,,,"iB8",,,"IS12~IT12","Z",,2097153,"IS12~IT12",C,201702270804,"-"

 3823,"20170227",4,753,29,"Dd",,"phH_1",,,,"iB8",,,"IS11~IT11","Z",,2097153,"IS11~IT11",C,201702270804,"-"

 3824,"20170227",5,753,30,"Dd",,"phH_1",,,,"iB8",,,"IS11~IT11","Z",,2097153,"IS11~IT11",C,201702270804,"-"

 3825,"20170227",6,753,7,"Dd",,"phH_1",,,,"iB8",,,"IS12~IT12","Z",,2097153,"IS12~IT12",C,201702270804,"-"

 3826,"20170227",7,753,327,"Dd",,"COV",,,,"AC1",,,,"Z",,2097153,,,201702270803,

 3827,"20170227",8,753,46,"Dd",,"ph_1",,,,"iB8",,,"IS10a~IS10b~IS10c~IS10d~IT10a~IT10b","Z",,2097153,"IS10a~IS10b~IS10c~IS10d~IT10a~IT10b",C,201702270804,"-"

我需要从这些数据中获得不同的片段，比如"20170217“，并将它们放入一个数组中以备后用。我该怎么做才是最好的呢？对于关心的人，我在下面添加了完整的代码片段！

https://jsfiddle.net/pztwfsq1/

Answer 1

由于每行只有一个数据集，因此可以遍历所有行。在,处拆分每一行，您将拥有一个信息数组。

类似于这个(给你一个概念)：

let row = "1,Peter,5,92,,Brooklyn"
let data = row.components(separatedBy: ",")

let name = data[1] // Peter
let location = data[5] // Brooklyn