我们使用Periscope,它(我认为)根据我们赋予其访问权限的表中存在的总行数收费。
我的问题是:给定一个用户periscope,如何获得用户periscope有权访问的表中的总行数?
例如,如果用户periscope只能访问两个表:计数为8的t1和计数为2的t2,则总计数应为10。
我用这个answer得到了所有的表(不包括'pg_tables‘和'information_schema'),但是我不知道下一步该怎么做:
SELECT CAST(schemaname as varchar), CAST( objectname as varchar)
FROM
(
SELECT
schemaname
,objectname
,usename
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'select') AS sel
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'insert') AS ins
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'update') AS upd
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'delete') AS del
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'references') AS ref
FROM
(
SELECT schemaname, 't' AS obj_type, tablename AS objectname, schemaname + '.' + tablename AS fullobj FROM pg_tables
WHERE schemaname not in ('pg_internal')
UNION
SELECT schemaname, 'v' AS obj_type, viewname AS objectname, schemaname + '.' + viewname AS fullobj FROM pg_views
WHERE schemaname not in ('pg_internal')
) AS objs
,(SELECT * FROM pg_user) AS usrs
ORDER BY fullobj
)
WHERE (sel = true or ins = true or upd = true or del = true or ref = true)
and usename = 'periscope'
and schemaname not in ('information_schema', 'pg_catalog');如果你有一个优雅的解决方案,请让我知道!
发布于 2016-09-08 05:01:03
这将为您提供所需的内容:
SELECT SUM(b.reltuples)
FROM
(
SELECT
schemaname
,objectname
,usename
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'select') AS sel
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'insert') AS ins
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'update') AS upd
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'delete') AS del
,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'references') AS ref
FROM
(
SELECT schemaname, 't' AS obj_type, tablename AS objectname, schemaname + '.' + tablename AS fullobj FROM pg_tables
WHERE schemaname not in ('pg_internal')
UNION
SELECT schemaname, 'v' AS obj_type, viewname AS objectname, schemaname + '.' + viewname AS fullobj FROM pg_views
WHERE schemaname not in ('pg_internal')
) AS objs
,(SELECT * FROM pg_user) AS usrs
ORDER BY fullobj
) as a
JOIN
(
SELECT
nspname AS schemaname,relname,reltuples
FROM pg_class C
LEFT JOIN pg_namespace N ON (N.oid = C.relnamespace)
ORDER BY reltuples DESC
) as b
ON (a.schemaname = b.schemaname AND a.objectname = b.relname)
WHERE (sel = true or ins = true or upd = true or del = true or ref = true)
and usename = 'periscope'
and a.schemaname not in ('information_schema', 'pg_catalog');https://stackoverflow.com/questions/39281900
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