循环多个变量以应用sound.Sound()心理函数

Question

我正在尝试将sound.Sound()函数应用于循环中的numpy数组。具体地说，我想在下面的循环中完成。a_wave到d_wave是numpy数组。

stim_a = sound.Sound(a_wave)
stim_b = sound.Sound(b_wave)
stim_c = sound.Sound(c_wave)
stim_d = sound.Sound(d_wave)

我已经尝试了下面的循环。

import sys
this = sys.modules[__name__]
import string

letters = list(string.ascii_lowercase)
a_d = letters[:4]
for x in range(len(a_d)):
    setattr(this, 'stim_%s' % a_d[x], sound.Sound('%s_wave' % a_d[x]))

但我得到了以下错误结果：

File "C:\Program Files (x86)\PsychoPy2\lib\site-packages\psychopy-1.83.01-py2.7.egg\psychopy\sound.py", line 389, in __init__
    self.setSound(value=value, secs=secs, octave=octave, hamming=hamming)
File "C:\Program Files (x86)\PsychoPy2\lib\site-packages\psychopy-1.83.01-py2.7.egg\psychopy\sound.py", line 146, in setSound
    raise ValueError, "setSound: could not find a sound file named " + value
ValueError: setSound: could not find a sound file named a_wave

如果我能在这件事上得到一些建议，我将不胜感激。我插入了下面的全部代码以供参考。

from __future__ import division
from psychopy import sound
import sys
this = sys.modules[__name__]
import numpy as np
import string

#generate string lists
letters = list(string.ascii_lowercase)
a_d = letters[:4]

sampling_rate = 44100 #in Hz
target_fq = 200
long_dur = 0.150
short_dur = 0.066
short_blank = 0.066
long_blank = 0.150
double_blank = 0.233

#short
short_index = np.array(range(int(round(short_dur / (1/float(sampling_rate)))-1)))
short_wave = np.sin(2*np.pi*target_fq*(short_index/float(sampling_rate)))
short_blank_wave = np.zeros(short_blank*sampling_rate) #Small fudge factor to bring total stim length to 4410

#long
long_index = np.array(range(int(round(long_dur / (1/float(sampling_rate)))-1)))
long_wave = np.sin(2*np.pi*target_fq*(long_index/float(sampling_rate)))
long_blank_wave = np.zeros(long_blank*sampling_rate)

#double blank
double_blank_wave = np.zeros(double_blank*sampling_rate)

#numpy arrays
a_wave = np.concatenate((long_wave, short_blank_wave, long_wave), axis=0)
b_wave = np.concatenate((short_wave, long_blank_wave, long_wave), axis=0)
c_wave = np.concatenate((long_wave, long_blank_wave, short_wave), axis=0)
d_wave = np.concatenate((short_wave, double_blank_wave, short_wave), axis=0)

for x in range(len(a_d)):
    setattr(this, 'stim_%s' % a_d[x], sound.Sound('%s_wave' % a_d[x]))

Answer 1

您(以一种非常复杂的方式)只是构造字符串(例如'a_wave')来传递给声音对象。声音对象自然地将它们解释为要打开的文件名，这将失败。也就是说，请注意字符串'a_wave'并不对应于您试图引用的numpy数组对象a_wave。

您可以简单地执行以下操作：

sound_stim = sound.Sound()

for sound_array in (a_wave, b_wave, c_wave, d_wave):

    for entry in sound_array:
        sound_stim.setSound(entry)
        sound_stim.play()
        # probably need some sort of delay loop here, as
        # playing doesn't block execution.

但是，由于您没有清楚地表达您试图实现的目标，我只是在这里猜测。注意，数组a_wave等根本不需要是numpy数组，它们可以只是Python列表，这将简化它们的构造。例如：

a_wave = [long_wave, short_blank_wave, long_wave]

一般来说，你过度设计了你的代码。保持简单和Pythonic风格。