Python在_sre.SRE_Match输出中的'match‘行？它能显示完全匹配吗？

Question

使用python 3：

In [275]: blah = "ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffg"

In [276]: pat = re.compile("([a-z]{2,9999})")

In [277]: data = re.search(pat,blah)

In [278]: data
Out[278]: <_sre.SRE_Match object; span=(0, 125), match='fffffffffffffffffffffffffffffffffffffffffffffffff>

match=''有可能打印出整个字符串吗？即一直到最终的'g'

Answer 1

不，这不可能。该长度是在match对象的repr方法的格式字符串中硬编码的，并不是为了捕获匹配字符串的完整长度而设计的。

除非您编译自己的CPython构建(或任何Python风格)，并修改match_repr中的match对象表示的精确度。默认精度为50：

result = PyUnicode_FromFormat(
        "<%s object; span=(%d, %d), match=%.50R>",
        Py_TYPE(self)->tp_name,
        self->mark[0], self->mark[1], group0);

正如其他人所建议的，只需使用match对象的group方法即可访问完整的匹配字符串。

Answer 2

使用这个方法，您可以不受任何重复次数上限的约束：

import re

blah = "ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffg"

r = re.compile(r'[a-z](.)\1{2,}') # no upper limit
try:
    re.search(r, blah).group()
except AttributeError:
    pass  # whatever you want to do when there is no match

Answer 3

您可能正在寻找.group ...

import re
blah = "ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffg"
pat = re.compile("([a-z]{2,99})")
data = re.search(pat,blah)
if data:
    data.group(0) # returns 'fffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff'
else:
    pass # do something when the string was not found!

请参阅：https://docs.python.org/3.5/library/re.html#re.match.group

和

Why won't re.groups() give me anything for my one correctly-matched group?