我在我的主页上有滑块横幅,没有链接到任何地方。我需要什么代码来为每个图像添加链接?是否可以使用下面的代码?
Thank you! I need to add a different link to each banner. The banners are all going to the printf('<a href="yourlink.html"> link. What am I doing wrong? <div id="home">
<div class="banner">
<div class="banner-slider">
<?php
if (!empty($options['slider_photo'])):
$slider_photos = explode(',', $options['slider_photo']);
foreach ($slider_photos as $k => $img):
printf('<a href="http://www.nemotile.com/tile/product/Handwritten/"><div class="banner-%d" style="background-image:url(%s)"></div></a>', $k, $img);
endforeach;
else: ?>
<a href="http://www.nemotile.com/tile/product/Handwritten/"><div class="banner-1"></div></a>
<a href="http://www.nemotile.com/tile/product/patchwork/"><div class="banner-2"></div>
<a href="http://www.nemotile.com/tile/product/BisazzaCementTiles/"><div class="banner-3"></div>
<div class="banner-5"></div>
<?php endif; ?>
</div>发布于 2017-08-11 22:31:05
您可以将此代码更改为下面的摘录。使用$i,您可以逐步遍历您的URL数组,这将为您提供它的一般过程。我不确定你是如何获得URL的,但这应该会带你走上正确的道路。
<div class="banner">
<div class="banner-slider">
<?php
$urls = ['URL1', 'URL2', 'URL3', 'URL4'];
$i = 0;
if (!empty($options['slider_photo'])):
$slider_photos = explode(',', $options['slider_photo']);
foreach ($slider_photos as $k => $img):
printf('<a href="'.$urls[$i].'"><div class="banner-%d" style="background-image:url(%s)"></div></a>', $k, $img);
$i++;
endforeach;
else: ?>
<a href="http://www.nemotile.com/tile/product/Handwritten/"><div class="banner-1"></div></a>
<a href="http://www.nemotile.com/tile/product/patchwork/"><div class="banner-2"></div>
<a href="http://www.nemotile.com/tile/product/BisazzaCementTiles/"><div class="banner-3"></div>
<div class="banner-5"></div>
<?php endif; ?>
</div>
https://stackoverflow.com/questions/45637643
复制相似问题