我会向你寻求帮助的。示例表:
| ID | NAME |POINT|
| 1 | alex | 2 |
| 2 | alex | 2 |
| 3 | jenn | 4 |
| 4 | shama| 3 |
| 5 | jenn | 4 |
| 6 | Mike | 1 |我想查找重复的名称,并更改名称的值和重复值的和。喜欢
| ID | NAME |POINT|
| 1 | alexander| 4 |
| 2 | jennifer | 8 |是否可以进行mysql查询?谢谢。
发布于 2017-03-02 05:11:56
尝尝这个
select id,
case when name = 'alex' then replace(NAME,'alex','alexander')
when name = 'jenn' then replace(NAME,'jenn','jennifer')
end as d,sum(point)
from name group by d having d is not null;发布于 2017-03-02 05:04:57
这是你想要的吗?
select (@rn := @rn + 1) as id, name, sum(point) as point
from t cross join
(select @rn := 0) params
group by name
having count(*) >= 2;https://stackoverflow.com/questions/42541990
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