我希望针对给定值对我的表运行一个查询,并根据是否找到行来返回一个Maybe a。
我有这个域名:
data User' a b c d e f = User { usrId :: a,
usrApproved :: b,
usrIden :: c,
usrImgUrl :: d,
usrTitle :: e,
usrUrl :: f
}
type User = User' Int Bool String String String String
$(makeAdaptorAndInstance "pUser" ''User')
type UserColumn = User' (Column PGInt4) (Column PGBool) (Column PGText) (Column PGText) (Column PGText) (Column PGText) 以及表和查询的以下定义:
userTable :: Table UserColumn UserColumn
userTable = Table "user" (pUser User { usrId = required "id",
usrApproved = required "approved",
usrIden = required "identifier",
usrImgUrl = required "img_url",
usrTitle = required "title",
usrUrl = required "url"
})
userQuery :: Query UserColumn
userQuery = queryTable userTable正如前面所暗示的,我想通过"identifier“列进行查询,所以我编写了这个查询,并希望返回一个` `IO (可能是User)
userByIdenQuery :: (Column PGText) -> Query UserColumn
userByIdenQuery iden = proc () -> do
user <- userQuery -< ()
restrict -< (adIden user) .=== iden
returnA -< user
getUserByIden :: String -> PGS.Connection -> IO (Maybe User)
getUserByIden iden c = do
usr <- runQuery c (userByIdenQuery $ pgString iden)
-- But this fails to compile
undefined -- just to minimise compilation errors这无法通过以下命令进行编译:
No instance for (Default
Opaleye.Internal.RunQuery.QueryRunner UserColumn haskells0)
arising from a use of `runQuery'
The type variable `haskells0' is ambiguous
Note: there is a potential instance available:
instance (product-profunctors-0.7.1.0:Data.Profunctor.Product.Class.ProductProfunctor
p,
Default p a1_0 a1_1, Default p a2_0 a2_1, Default p a3_0 a3_1,
Default p a4_0 a4_1, Default p a5_0 a5_1, Default p a6_0 a6_1) =>
Default
p
(User' a1_0 a2_0 a3_0 a4_0 a5_0 a6_0)
(User' a1_1 a2_1 a3_1 a4_1 a5_1 a6_1)
-- Defined at src\DB.hs:33:3
In a stmt of a 'do' block:
usr <- runQuery c (userByIdenQuery $ pgString iden)
In the expression:
do { usr <- runQuery c (userByIdenQuery $ pgString iden);
undefined }
In an equation for `getUserByIden':
getUserByIden iden c
= do { usr <- runQuery c (userByIdenQuery $ pgString iden);
undefined }如果我尝试实现这个函数:
getUserByIden :: String -> PGS.Connection -> IO (Maybe User)
getUserByIden iden c = do
(usrId, appr, idn, imUrl, tit, url) <- runQuery c (userByIdenQuery $ pgString iden)
return $ Just $ User usrId appr idn imUrl tit url然后我就会看到这个编译错误:
Couldn't match expected type `[haskells0]'
with actual type `(Int, Bool, String, String, String, String)'
In the pattern: (usrId, appr, idn, imUrl, tit, url)
In a stmt of a 'do' block:
(usrId, appr, idn, imUrl, tit, url) <- runQuery
c (userByIdenQuery $ pgString iden)
In the expression:
do { (usrId, appr, idn, imUrl, tit, url) <- runQuery
c (userByIdenQuery $ pgString iden);
return $ Just $ User usrId appr idn imUrl tit url }
I really have no idea where to go with this, other than using a library other than Opaleye.发布于 2016-09-03 22:10:03
我不熟悉OpalEye,但我认为您可能只需要明智地使用listToMaybe (import Data.Maybe (listToMaybe))
getUserByIden :: String -> PGS.Connection -> IO (Maybe User)
getUserByIden iden c = do
listToMaybe <$> runQuery c (userByIdenQuery $ pgString iden)发布于 2016-09-03 23:13:54
我认为问题出在您在函数getUserByIden的末尾使用undefined。由于Opaleye在幕后做了一些复杂的类型级别的魔术,你需要为runQuery的使用指定一个类型,或者简单地返回生成的值而不是未定义的值,因为未定义会使顶级推理算法有点混乱:
getUserByIden :: String -> PGS.Connection -> IO (Maybe User)
getUserByIden iden c = listToMaybe <$> runQuery c (userByIdenQuery $ pgString iden)我还添加了一个listToMaybe调用来更改函数体的类型,以匹配您指定的返回类型。完全应用runQuery时,将返回IO [SomeHaskellType]类型的值,而不是IO (Maybe SomeHaskellType)类型的值。
https://stackoverflow.com/questions/39305513
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