使用xslt-3合并两个或多个xml文件

Question

我有许多XML文件，需要将它们合并到一个文件中: to 1.xml

<?xml version="1.0" encoding="UTF-8"?>
<menu>
<breakfast_menu>

<food>
<name>Belgian Waffles</name>
<price>$5.95</price>
<description>Two of our famous Belgian Waffles with plenty of real maple syrup</description>
<calories>650</calories>
</food>

<food>
<name>Strawberry Belgian Waffles</name>
<price>$7.95</price>
<description>Light Belgian waffles covered with strawberries and whipped cream</description>
<calories>900</calories>
</food>

</breakfast_menu>
</menu>

hotel2：

<?xml version="1.0" encoding="UTF-8"?>
<menu>
<breakfast_menu>

<food>
<name>Berry-Berry Belgian Waffles</name>
<price>$8.95</price>
<description>Light Belgian waffles covered with an assortment of fresh berries and whipped cream</description>
<calories>900</calories>
</food>

</breakfast_menu>
</menu>

System3.xml：

<?xml version="1.0" encoding="UTF-8"?>
<menu>
<breakfast_menu>

<food>
<name>French Toast</name>
<price>$4.50</price>
<description>Thick slices made from our homemade sourdough bread</description>
<calories>600</calories>
</food>

<food>
<name>Homestyle Breakfast</name>
<price>$6.95</price>
<description>Two eggs, bacon or sausage, toast, and our ever-popular hash browns</description>
<calories>950</calories>
</food>

</breakfast_menu>
</menu>

我首先需要向name元素添加一个值，以便知道它来自哪个文件，并合并所有xml文件。

所需输出：

<?xml version="1.0" encoding="UTF-8"?>
<menu>
<breakfast_menu>

<food>
<name>Belgian Waffles-hotel1</name>
<price>$5.95</price>
<description>Two of our famous Belgian Waffles with plenty of real maple syrup</description>
<calories>650</calories>
</food>

<food>
<name>Strawberry Belgian Waffles-hotel1</name>
<price>$7.95</price>
<description>Light Belgian waffles covered with strawberries and whipped cream</description>
<calories>900</calories>
</food>

<food>
<name>Berry-Berry Belgian Waffles-hotel2</name>
<price>$8.95</price>
<description>Light Belgian waffles covered with an assortment of fresh berries and whipped cream</description>
<calories>900</calories>
</food>

<food>
<name>French Toast-hotel3</name>
<price>$4.50</price>
<description>Thick slices made from our homemade sourdough bread</description>
<calories>600</calories>
</food>

<food>
<name>Homestyle Breakfast-hotel3</name>
<price>$6.95</price>
<description>Two eggs, bacon or sausage, toast, and our ever-popular hash browns</description>
<calories>950</calories>
</food>

</breakfast_menu>
</menu>

在给定的文件夹中，我需要将所有xml文件合并到一个文件夹中。只需合并它们的内容。无检查或更新。此外，我还需要在name元素中保留每个文件的来源，以备将来参考

这是我的试验。我需要有人更有经验的帮助，以便使用最新的xslt-3，并作为xml文件存在于给定的文件夹。

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output indent="yes"/>

  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()" />
    </xsl:copy>
  </xsl:template>

  <xsl:template match="breakfast_menu">
    <xsl:copy>
      <xsl:apply-templates select="*"/>
      <xsl:apply-templates select="document('hotel1.xml')/menu/breakfast_menu/*" />
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

Answer 1

在XSLT中有多种方法可以做到这一点，一种是尝试新的xsl:merge指令，但是当我在使用Saxon9.8(参见https://saxonica.plan.io/issues/3883和https://saxonica.plan.io/issues/3884)时遇到问题时，这里是一种不同的方法，看起来你只是想复制来自某一层的所有元素，在你的例子中是来自第三层的food元素；执行此操作的通用样式表将select表达式作为静态参数(我将其作为*/*/*通用，但您当然可以将其拼写为menu/breakfast_menu/food)、URI和输入文件的文件名模式，然后以xsl:initial-template (Saxon命令行的命令行选项-it )启动，如下所示：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:mf="http://example.com/mf"
    exclude-result-prefixes="#all"
    expand-text="yes"
    version="3.0">

    <xsl:param name="input-uri" as="xs:string" select="'.'"/>

    <xsl:param name="file-pattern" as="xs:string" select="'hotel*.xml'"/>

    <xsl:param name="merge-select-expression" as="xs:string" static="yes" select="'*/*/*'"/>

    <xsl:param name="xslt-pattern-to-add-file-name" as="xs:string" static="yes" select="$merge-select-expression || '/name'"/>

    <xsl:output indent="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:mode on-no-match="shallow-copy" streamable="yes"/>

    <xsl:template _match="{$xslt-pattern-to-add-file-name}">
        <xsl:comment>Copied this {node-name()} element from {tokenize(document-uri(/), '/')[last()]}</xsl:comment>
        <xsl:next-match/>
    </xsl:template>

    <xsl:template name="xsl:initial-template">
        <xsl:sequence select="mf:append-docs(uri-collection($input-uri || '?select=' || $file-pattern))"/>
    </xsl:template>

    <xsl:function name="mf:append-docs" as="document-node()">
        <xsl:param name="doc-uris" as="xs:anyURI+"/>
        <xsl:source-document href="{head($doc-uris)}" streamable="yes">
            <xsl:apply-templates select="." mode="construct">
                <xsl:with-param name="remaining-doc-uris" as="xs:anyURI*" select="tail($doc-uris)" tunnel="yes"/>
            </xsl:apply-templates>
        </xsl:source-document>
    </xsl:function>

    <xsl:mode name="construct" on-no-match="shallow-copy" streamable="yes"/>

    <xsl:template _match="{string-join(tokenize($merge-select-expression, '/')[position() lt last()], '/')}" mode="construct">
        <xsl:param name="remaining-doc-uris" as="xs:anyURI*" tunnel="yes"/>
        <xsl:copy>
            <xsl:apply-templates select="@*"/>
            <xsl:apply-templates/>
            <xsl:for-each select="$remaining-doc-uris">
                <xsl:source-document href="{.}" streamable="yes">
                    <xsl:apply-templates _select="{$merge-select-expression}"/>
                </xsl:source-document>
            </xsl:for-each>
        </xsl:copy>
    </xsl:template>

</xsl:stylesheet>

只需简单地调整参数，也许还可以调整<xsl:template _match="{$xslt-pattern-to-add-file-name}">模板的主体，因为我选择了在注释中输出文件名，而不是将其放入元素的内容中。

对于样式表append.xsl所在的子目录hotel-stackoverflow-test和Saxon命令行-it -xsl:.\append.xsl input-uri=hotel-stackoverflow-test file-pattern=hotel*.xml中的三个示例，我将获得输出

<menu>
   <breakfast_menu>
      <food><!--Copied this name element from hotel1.xml-->
         <name>Belgian Waffles</name>
         <price>$5.95</price>
         <description>Two of our famous Belgian Waffles with plenty of real maple syrup</description>
         <calories>650</calories>
      </food>
      <food><!--Copied this name element from hotel1.xml-->
         <name>Strawberry Belgian Waffles</name>
         <price>$7.95</price>
         <description>Light Belgian waffles covered with strawberries and whipped cream</description>
         <calories>900</calories>
      </food>
      <food><!--Copied this name element from hotel2.xml-->
         <name>Berry-Berry Belgian Waffles</name>
         <price>$8.95</price>
         <description>Light Belgian waffles covered with an assortment of fresh berries and whipped cream</description>
         <calories>900</calories>
      </food>
      <food><!--Copied this name element from hotel3.xml-->
         <name>French Toast</name>
         <price>$4.50</price>
         <description>Thick slices made from our homemade sourdough bread</description>
         <calories>600</calories>
      </food>
      <food><!--Copied this name element from hotel3.xml-->
         <name>Homestyle Breakfast</name>
         <price>$6.95</price>
         <description>Two eggs, bacon or sausage, toast, and our ever-popular hash browns</description>
         <calories>950</calories>
      </food>
   </breakfast_menu>
</menu>

代码应该在Saxon 9.8 EE中使用流式处理，在Saxon 9.8 HE或PE中使用普通XSLT处理。