如何在MiUi pre - Marshmallow中请求权限？

Question

int permissionCheck = ContextCompat.checkSelfPermission(mActivity, Manifest.permission.RECEIVE_SMS);

ActivityCompat.requestPermissions(this,
            new String[]{Manifest.permission.READ_CONTACTS},
            PERMISSION_REQUEST_CODE);

Log.d(TAG, permissionCheck + "");

权限检查总是返回PERMISSION_GRANTED，但在操作系统(MiUi)中，应用程序没有权限。

测试设备: Redmi Note 3 Pro (MIUI 8)

Answer 1

在miui中，你需要在不同的way.You中询问权限，需要检查权限模式是否等于零。在上面的棉花糖中检查此函数的读取sms权限

private boolean checkUsagePermission() {
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.M) {
    AppOpsManager appOps = (AppOpsManager) getSystemService(Context.APP_OPS_SERVICE);
    int mode = 0;
    mode = appOps.checkOpNoThrow("android:read_sms", android.os.Process.myUid(), getPackageName());
    boolean granted = mode == AppOpsManager.MODE_ALLOWED;
    if (!granted) {
        //write your code for accept that permission
        return false;
    }
}
return true;
}

一旦你在你的android studio中查看了AppOpsManager类。

Answer 2

对于某些权限，我使用这样的方法：

private boolean permissionsActivated = (Build.VERSION.SDK_INT < Build.VERSION_CODES.M);

@Override
    protected void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);
//....
        requirepermissionsifneeded();
//....
    }

    @SuppressLint("NewApi")
        private void requirepermissionsifneeded() {
            // TODO Auto-generated method stub
            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
                if (!canAll()) {
                    permissionsActivated = false;
                    requestPermissions(INITIAL_PERMS, REQUESTPERM);
                } 

else {
permissionsActivated = true;
}
            } else {
                permissionsActivated = true;
            }
        }


@SuppressLint("NewApi")
    private boolean hasPermission(String perm) {
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
            return (PackageManager.PERMISSION_GRANTED == checkSelfPermission(perm));
        } else {
            return true;
        }
        }
private boolean canAll() {
        // TODO Auto-generated method stub
        return (canAccessLocation() && canCoarseLocation() && canGetAccounts());
    }
    private boolean canAccessLocation() {
        return hasPermission(android.Manifest.permission.ACCESS_FINE_LOCATION);
    }
    private boolean canCoarseLocation() {
        return hasPermission(android.Manifest.permission.ACCESS_COARSE_LOCATION);
    }
    private boolean canGetAccounts() {
        return hasPermission(android.Manifest.permission.GET_ACCOUNTS);
    }
    @Override
    public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
        // TODO Auto-generated method stub
        super.onRequestPermissionsResult(requestCode, permissions, grantResults);
        switch (requestCode) {
            case REQUESTPERM: {
                // If request is cancelled, the result arrays are empty.
                if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                    permissionsActivated = true;
                } else {
                    // permission denied, boo! Disable the
                    // functionality that depends on this permission.
                    Toast.makeText(this, ":(", Toast.LENGTH_LONG).show();
                    permissionsActivated = false;
                }
            return;
            }
            // other 'case' lines to check for other
            // permissions this app might request
        }
    }

代码中的某处

permissionsActivated = canAll();

Answer 3

对于下面的API 23，我们通常假设我们的应用程序将拥有清单中声明的所有权限，小米是一个例外。

您可以做的是将您的代码放在try catch块中，看看是否可以使用抛出的异常识别场景。

我没有这样的设备，所以不能测试这个。我猜它会抛出一个SecurityException。

不过，对于接收短信的权限，我不认为你可以这样做。相反，应在安装时通知用户不要禁用权限。或者你可以要求用户将其设置为默认的短信应用程序。

一定要试一试，让我们知道！