您好,我正在尝试使用genderizer包在R中创建一个饼图。我指的是来自网站https://www.r-bloggers.com/the-gender-of-big-data/的以下代码
library(rvest)
library(stringr)
library(dplyr)
library(genderizeR)
library(ggplot2)
library(googleVis)
paste0("http://www.crn.com/slide-shows/data-center/300076704/2015-big-data-
100-business-analytics.htm/pgno/0/", 1:45) %>%
c(., paste0("http://www.crn.com/slide-shows/data-center/300076709/2015-big-
data-100-data-management.htm/pgno/0/",1:30)) %>%
c(., paste0("http://www.crn.com/slide-shows/data-center/300076740/2015-big-
data-100-infrastructure-tools-and-services.htm/pgno/0/",1:25)) -> webpages
results=data.frame()
for(x in webpages)
{
read_html(x) %>% html_nodes("p:nth-child(1)") %>% .[[2]] %>% html_text() ->
Company
read_html(x) %>% html_nodes("p:nth-child(2)") %>% .[[1]] %>% html_text() ->
Executive
results=rbind(results, data.frame(Company, Executive))
}
results=data.frame(lapply(results, as.character), stringsAsFactors=FALSE)
results[74,]=c("Trifacta", "Top Executive: CEO Adam Wilson")
results %>%
mutate(Name=gsub("Top|\bExec\S*|\bCEO\S*|President|Founder|and|Co-
Founder|\:", "", Executive)) %>%
mutate(Name=word(str_trim(Name))) -> results
results %>%
select(Name) %>%
findGivenNames() %>%
filter(probability > 0.9 & count > 15) %>%
as.data.frame() -> data
data %>% group_by(gender) %>% summarize(Total=n()) -> dat
doughnut=gvisPieChart(dat,
options=list(
width=450,
height=450,
legend="{ position: 'bottom', textStyle: {fontSize: 10}}",
chartArea="{left:25,top:50}",
title='TOP 100 BIG DATA COMPANIES 2015
Gender of CEOs',
colors="['red','blue']",
pieHole=0.5),
chartid="doughnut")
plot(doughnut)它抛出一个错误,说没有找到变异函数,我已经正确安装了所有的包。有人能带我到这里来吗?
或者有人可以分享使用R和Sparklyr创建饼图的示例代码。这是我的第一个任务,我只是想理解这个概念。提亚
发布于 2017-08-15 08:47:29
如果您使用的不是饼图,而是条形图,请尝试这个包:https://github.com/edgararuiz/dbplot
https://stackoverflow.com/questions/45558749
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