我正在尝试使用sbt-scalaxb为FixRepository.xsd生成绑定,但它不像SUBJ。
当然,作为最后的手段,我可以稍微修改一下模式,但是是否有一种方法可以调优sbt-scalaxb以理解原始文件?
sbt-scalaxb不喜欢的XSD片段是:
xml <xs:element name="component"> <xs:complexType> <xs:sequence> <xs:element ref="messageEntity" minOccurs="0" maxOccurs="unbounded"/> </xs:sequence> <xs:attributeGroup ref="entityAttribGrp"/> <xs:attribute name="id" type="id_t" use="required"/> <xs:attribute name="name" type="xs:string" use="required"/> <xs:attribute name="type" type="ComponentType_t" use="required"/> <xs:attribute name="repeating" type="BOOL_t" use="optional"/> <xs:attribute name="category" type="xs:string" use="optional"/> <xs:attribute name="abbrName" type="xs:string" use="optional"/> <xs:attribute name="notReqXML" type="BOOL_t" use="optional"/> <!-- would like to force a description of the component --> </xs:complexType> </xs:element>
发布于 2018-08-26 21:50:25
我自己想出来了:scalaxbAttributePrefix设置为属性属性添加了一个前缀。
build.sbt
scalaxbAttributePrefix in (Compile, scalaxb) := Some("attr")生成的FixRepository.scala
case class Fix(
...,
components: ...fixrepo.Components,
...,
attributes: Map[String, scalaxb.DataRecord[Any]] = Map()
) {
...
lazy val attrComponents = attributes("@components").as[BOOL_t]
...
}https://stackoverflow.com/questions/52025304
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