Hibernate elasticsearch音译(ICU转换)

Question

我使用的是hibernate-search和hibernate-search-elasticsearch版本5.10.3.Final。我想在一些领域应用ICU变换。以下是elasticsearch文档中的过滤器：

https://www.elastic.co/guide/en/elasticsearch/plugins/5.6/analysis-icu-transform.html

但是我在hibernate-search依赖项使用的lucene版本中找不到аTokenFilterFactory。在TokenFilterDef中，工厂属性是必需的。有人知道如何使用hibernate-search实现音译吗？

Answer 1

您可以使用注释并依赖于org.hibernate.search.elasticsearch.analyzer.ElasticsearchTokenFilterFactory来创建JSON令牌过滤器定义：

@AnalyzerDef(
    name = "myAnalyzer",
    tokenizer = ...,
    filter = @TokenFilterDef(
        name = "myLatinTransform",
        factory = ElasticsearchTokenFilterFactory.class,
        params = {
            @Parameter(name = "type", value = "'icu_transform'"),
            @Parameter(name = "id", value = "'Any-Latin; NFD; [:Nonspacing Mark:] Remove; NFC'")
        }
    )
)

注意:参数值被解释为JSON，因此字符串值必须用引号括起来。不过，为了方便起见，允许使用单引号。

请参阅https://docs.jboss.org/hibernate/search/5.10/reference/en-US/html_single/#_custom_analyzers_using_the_code_analyzerdef_code_annotation

或者，您可以通过编程方式定义分析器，并从更自然的API中获益：

# In hibernate.properties
hibernate.search.elasticsearch.analysis_definition_provider com.acme.CustomAnalyzerProvider

public class CustomAnalyzerProvider implements ElasticsearchAnalysisDefinitionProvider {
    @Override
    public void register(ElasticsearchAnalysisDefinitionRegistryBuilder builder) {
        builder.analyzer( "myAnalyzer" )
                .withTokenizer( "whitespace" )
                .withTokenFilter( "myLatinTransform" );

        builder.tokenFilter( "myLatinTransform" )
                .type( "icu_transform" )
                .param( "id", "Any-Latin; NFD; [:Nonspacing Mark:] Remove; NFC" );
    }
}

请参阅https://docs.jboss.org/hibernate/search/5.10/reference/en-US/html_single/#_custom_analyzers_using_a_definition_provider