首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >Scrapy traceback错误(无效语法)

Scrapy traceback错误(无效语法)
EN

Stack Overflow用户
提问于 2018-02-19 07:27:01
回答 1查看 226关注 0票数 0

我已经关注了几个教程,并且不断地获得SyntaxError

代码语言:javascript
复制
C:\Users\Luis\mercado>scrapy crawl mercado -t csv
Traceback (most recent call last):
  File "C:\Users\Luis\Anaconda2\Scripts\scrapy-script.py", line 5, in 
<module>
    sys.exit(scrapy.cmdline.execute())
  File "C:\Users\Luis\Anaconda2\lib\site-packages\scrapy\cmdline.py", line 
149,
in execute
    cmd.crawler_process = CrawlerProcess(settings)
  File "C:\Users\Luis\Anaconda2\lib\site-packages\scrapy\crawler.py", line 
249,
in __init__
    super(CrawlerProcess, self).__init__(settings)
  File "C:\Users\Luis\Anaconda2\lib\site-packages\scrapy\crawler.py", line 
137,
in __init__
    self.spider_loader = _get_spider_loader(settings)
  File "C:\Users\Luis\Anaconda2\lib\site-packages\scrapy\crawler.py", line 
336,
in _get_spider_loader
    return loader_cls.from_settings(settings.frozencopy())
  File "C:\Users\Luis\Anaconda2\lib\site-packages\scrapy\spiderloader.py", 
line 61, in from_settings return cls(settings)
  File "C:\Users\Luis\Anaconda2\lib\site-packages\scrapy\spiderloader.py", 
line 25, in __init__
    self._load_all_spiders()
  File "C:\Users\Luis\Anaconda2\lib\site-packages\scrapy\spiderloader.py", 
line 47, in _load_all_spiders
   for module in walk_modules(name):
  File "C:\Users\Luis\Anaconda2\lib\site-packages\scrapy\utils\misc.py", 
line 71
, in walk_modules
    submod = import_module(fullpath)
  File "C:\Users\Luis\Anaconda2\lib\importlib\__init__.py", line 37, in 
import_module
    __import__(name)
      File "C:\Users\Luis\mercado\mercado\spiders\spider.py",     line 7
            Class MercadoSpider(CrawlSpider):
SyntaxError: invalid syntax

你能帮我拿一下吗?

EN

回答 1

Stack Overflow用户

发布于 2018-02-19 08:17:48

在Python中,class总是以小写形式编写。您的Python中存在语法错误。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/48857724

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档