API网关- Lambda代理集成和异步调用

Question

如果我设置了一个头X-Amz-Invocation-Type：'Event'，调用是异步完成的，但正如亚马逊文档(https://docs.aws.amazon.com/apigateway/latest/developerguide/api-gateway-set-up-simple-proxy.html#api-gateway-simple-proxy-for-lambda-output-format)所述，当使用代理Lambda Integration时，lambda函数必须返回这种格式良好的响应：

callback(null, {"statusCode": 200, "body": "results"})

由于lambda函数是异步调用的，因此API Gateway永远不会得到应答，然后返回502 Bad Gateway error而不是200OK状态。

下面是swagger配置的摘录：

"/myFunc": {
  "post": {
    "parameters": [
      {
        "name": "myparam",
        "in": "query",
        "required": true,
        "type": "string"
      }
    ],
    "responses": {
      "200": {
        "description": "200 response"
      }
    },
    "x-amazon-apigateway-request-validator": "Validate query string parameters and headers",
    "x-amazon-apigateway-integration": {
      "responses": {
        "default": {
          "statusCode": "200"
        }
      },
      "uri": "arn:aws:apigateway:ap-northeast-1:lambda:path/2015-03-31/functions/arn:aws:lambda:ap-northeast-1:idAccount:function:myFunc/invocations",
      "passthroughBehavior": "when_no_match",
      "httpMethod": "POST",
      "type": "aws_proxy",
      "requestParameters": {
        "integration.request.header.X-Amz-Invocation-Type": "'Event'"
      }
    }
  }
}

有没有办法让它工作呢？

Answer 1

你可以设置一个自定义的lambda集成(没有代理标志)。您将需要配置映射模板以将请求/响应转换为所需的格式。

http://docs.aws.amazon.com/apigateway/latest/developerguide/getting-started-lambda-non-proxy-integration.html#getting-started-new-lambda