我正在设置一个具有许多数据库的Django应用程序,其中一些数据库使用相同的模型(它们不是副本)。我已经配置了我的路由器,一切都运行得很好。当我想使用factory-boy进行测试时,出现了这个问题。
在不同的项目中,我可以在Meta中设置数据库,但现在,我必须选择在哪个数据库上动态创建实例(如果不是这样,我将不得不为每个数据库创建一个DjangoModelFactory,这不是很好)。
有没有一种(更简单的)方法来为每次创建动态指定数据库?
发布于 2018-02-17 01:00:13
据我所知,factory_boy (version <=2.10.0)没有提供这样的功能。
不过,您的问题是使用上下文管理器的完美用例。它将允许您在需要的任何地方动态设置数据库,并且仅在所需的范围内设置,并且还可以干式!:
# factoryboy_utils.py
@classmethod
def _get_manager(cls, model_class):
return super(cls, cls)._get_manager(model_class).using(cls.database)
class DBAwareFactory(object):
"""
Context manager to make model factories db aware
Usage:
with DBAwareFactory(PersonFactory, 'db_qa') as personfactory_on_qa:
person_on_qa = personfactory_on_qa()
...
"""
def __init__(self, cls, db):
# Take a copy of the original cls
self.original_cls = cls
# Patch with needed bits for dynamic db support
setattr(cls, 'database', db)
setattr(cls, '_get_manager', _get_manager)
# save the patched class
self.patched_cls = cls
def __enter__(self):
return self.patched_cls
def __exit__(self, type, value, traceback):
return self.original_cls然后,在你的测试中,你可以这样做:
from factoryboy_utils import DBAwareFactory
class MyTest(TestCase):
def test_mymodel_on_db1(self):
...
with DBAwareFactory(MyModelFactory, 'db1') as MyModelFactoryForDB1:
mymodelinstance_on_db1 = MyModelFactoryForDB1()
# whatever you need with that model instance
...
# something else here
def test_mymodel_on_db2(self):
...
with DBAwareFactory(MyModelFactory, 'db2') as MyModelFactoryForDB2:
mymodelinstance_on_db2 = MyModelFactoryForDB2()
# whatever you need with that model instance
...
# something else herehttps://stackoverflow.com/questions/48753155
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