在Plotly ValueError中使用Pandas对象

Question

作为Python课程的一部分，我正在尝试使用Plotly off of a DataFrame创建一个图表。DataFrame是从本地csv文件创建的，工作正常。

cars = pd.read_csv(r'C:\Users\arman\OneDrive\Desktop\mtcars.csv')
cars.columns = ['car_names','mpg','cyl','disp', 'hp', 'drat', 'wt', 'qsec', 'vs', 'am', 'gear', 'carb']
df = cars[['cyl', 'wt','mpg']]
layouts = dict(title = 'Chart From Pandas DataFrame', xaxis= dict(title='x-axis'), yaxis= dict(title='y-axis'))
df.iplot(filename='cf-simple-line-chart', layout= layouts)

运行此程序时，我得到以下错误：

ValueError: the data property of a figure may only be assigned a list or tuple that contains a permutation of a subset of itself Invalid trace(s) with uid(s): set([None])

ValueErrorTraceback (most recent call last)
<ipython-input-9-9d51de7f2e8a> in <module>()
  6 cars_select.columns = ['mpg', 'disp', 'hp']
  7 
----> 8 cars_select.iplot(kind='histogram', filename='multiple-histogram-chart')
C:\Users\arman\AppData\Local\Continuum\anaconda2\lib\site-packages\cufflinks\plotlytools.pyc in _iplot(self, data, layout, filename, sharing, kind, title, xTitle, yTitle, zTitle, theme, colors, colorscale, fill, width, dash, mode, symbol, size, barmode, sortbars, bargap, bargroupgap, bins, histnorm, histfunc, orientation, boxpoints, annotations, keys, bestfit, bestfit_colors, mean, mean_colors, categories, x, y, z, text, gridcolor, zerolinecolor, margin, labels, values, secondary_y, subplots, shape, error_x, error_y, error_type, locations, lon, lat, asFrame, asDates, asFigure, asImage, dimensions, asPlot, asUrl, online, **kwargs)
899 ## Figure defintion
900         figure=Figure()
--> 901         figure['data']=data
902         figure['layout']=layout
903 
C:\Users\arman\AppData\Local\Continuum\anaconda2\lib\site-packages\plotly\basedatatypes.pyc in __setitem__(self, prop, value)
234 
235             if prop == 'data':
--> 236                 self.data = value
237             elif prop == 'layout':
238                 self.layout = value
C:\Users\arman\AppData\Local\Continuum\anaconda2\lib\site-packages\plotly\basedatatypes.pyc in __setattr__(self, prop, value)
266         if prop.startswith('_') or hasattr(self, prop):
267             # Let known properties and private properties through
--> 268             super(BaseFigure, self).__setattr__(prop, value)
269         else:
270             # Raise error on unknown public properties
C:\Users\arman\AppData\Local\Continuum\anaconda2\lib\site-packages\plotly\basedatatypes.pyc in data(self, new_data)
439                 .format(invalid_uids=invalid_uids))
440 
--> 441             raise ValueError(err_msg)
442 
443         # ### Check for duplicates in assignment ###
ValueError: The data property of a figure may only be assigned a list or tuple that contains a permutation of a subset of itself
Invalid trace(s) with uid(s): set([None])

任何帮助都将不胜感激。

编辑:我已经发布了示例数据集的图像(不确定发布csv文件的最佳格式；但如果有帮助，我从Lynda.com上的Python for Data Science Essential Training课程中获得了此文件) mtcars csv file

我还尝试用以下DataFrames创建绘图：

df = pd.DataFrame(np.random.randn(1000, 4), columns=['a', 'b', 'c', 'd'
df.scatter_matrix(filename='cufflinks/scatter-matrix', world_readable=True)

和

df = cf.datagen.lines()
df.iplot(kind='scatter', filename='cufflinks/cf-simple-line')

两个示例DataFrames都会产生相同的错误。我猜这可能是袖扣的问题。我目前运行的是0.8.2版本。

Answer 1

感谢大家的帮助。发现问题出在安装Plotly时，它安装了3.1.1版本而不是2.7.0版本，从而产生了此错误。在重新安装2.7.0版本时，我能够绘制我想要绘制的图形。