我已经创建了扩展的警报管理器: interface
public interface AlertManagerExt extends AlertManager {
void successCode(String messageCode, Object... args);
void infoCode(String messageCode, Object... args);
void warnCode(String messageCode, Object... args);
void errorCode(String messageCode, Object... args);
}和实现
public class AlertManagerExtImpl extends AlertManagerImpl implements AlertManagerExt {
private final Messages messages;
public AlertManagerExtImpl(ApplicationStateManager asm, Request request, AjaxResponseRenderer ajaxResponseRenderer,
PerthreadManager perThreadManager, Messages messages) {
super(asm, request, ajaxResponseRenderer, perThreadManager);
this.messages = messages;
}
@Override
public void successCode(String messageCode, Object... args) {
success(getMessage(messageCode, args));
}
@Override
public void infoCode(String messageCode, Object... args) {
info(getMessage(messageCode, args));
}
@Override
public void warnCode(String messageCode, Object... args) {
warn(getMessage(messageCode, args));
}
@Override
public void errorCode(String messageCode, Object... args) {
error(getMessage(messageCode, args));
}
protected String getMessage(String code, Object... args) {
if (args.length > 0) {
return messages.format(code, args);
}
return messages.get(code);
}
}当我试图通过绑定器绑定它时:
binder.bind(AlertManagerExt.class, AlertManagerExtImpl.class);我得到了异常:
java.lang.RuntimeException: Service interface org.apache.tapestry5.alerts.AlertManager is matched by 2 services: AlertManager, AlertManagerExtImpl. Automatic dependency resolution requires that exactly one service implement the interface.
at org.apache.tapestry5.ioc.internal.RegistryImpl.getServiceByTypeAlone(RegistryImpl.java:789)
at org.apache.tapestry5.ioc.internal.RegistryImpl.getServiceByTypeAndMarkers(RegistryImpl.java:797)
at org.apache.tapestry5.ioc.internal.RegistryImpl.getService(RegistryImpl.java:755)我知道我可以复制粘贴AlertManager中的所有方法,而不需要扩展它。但也许有更好的方法呢?
发布于 2017-03-10 18:14:53
这是因为当您尝试仅按接口类型对接口进行@Inject时,Tapestry IoC会尝试查找实现该接口的所有服务。您的新AlertManagerExt也实现了AlertManager,因此产生了歧义。
这通常是通过显式指定服务ID或标记注释来解决的,但这不适用于您的情况,因为tapestry的核心代码已经通过接口对AlertManager进行了@Inject。
发布于 2017-03-07 18:09:23
您可以通过几种方式来完成此任务,具体取决于您真正需要的内容。我邀请您阅读documentation和IoC cookbook。
了解控制反转配置非常重要,因为它是一个非常强大的模块。
https://stackoverflow.com/questions/42642853
复制相似问题