如何捕捉“- Started abcApplication in 12.49秒”事件？

Question

语言:Java，框架:Springboot，应用程序名称: abcApplication "21:47:32.133 main INFO c.c.abc.abcApplication - Started abcApplication in12.49秒(JVM运行8.467)“

我正在用Springboot开发一个web应用程序。当应用程序成功启动时，springboot-application会输出上述消息。如何处理此事件？当应用程序初始化完成时，我想做一些事情。

Answer 1

您正在寻找的是ContextRefreshedEvent，您可以创建一个类并使其成为组件并实现ApplicationListener

@Component
public class ServerReadyClass implements  ApplicationListener<ContextRefreshedEvent> {

    @Override
    public void onApplicationEvent(ContextRefreshedEvent event) {
        //YOUR LOGIC
    }
}

Answer 2

你也可以听ApplicationReadyEvent。

@Configuration
public class ProjectConfiguration {
    private static final Logger log = 
   LoggerFactory.getLogger(ProjectConfiguration.class);

   @EventListener(ApplicationReadyEvent.class)
   public void doSomethingAfterStartup() {
    log.info("hello world, I have just started up");
  }
}