我有一张这样的桌子:
declare @rooms table
(
depa_key int,
room_key int,
d1 int,
d2 int
)
insert into @rooms(depa_key, room_key, d1, d2)
select 1, null, null, null
union all
select 1, 1, 1, 1
union all
select 1, 1, 1, 1
union all
select 2, null, null, null
union all
select 2, 1, 5, 3
union all
select 2, 1, 7, 2
union all
select 3, null, null, null
union all
select 3, 1, 6, 9
union all
select 3, 1, 5, 8表中填充了:

我想要做的(但我不知道如何做)是填充汇总行(使用来自该depa_key的摘要填充romm_key is null的行)。
room_key为null的行是汇总行。只有部门没有room_key (因为部门意味着所有房间)。每个房间都有room_key和depa_key。
示例:
第一行(depa_key = 1,room_key = NULL)应填充:
D1 D2
2 2第二行(depa_key = 2,room_key = NULL)应填充:
D1 D2
12 5将来会有很多depa_keys (表是动态变化的),所以查询也必须是动态的。我可以逐个输入depa_keys (更新查询),但我不能这样做。如何使用depa_key中摘要动态更新列d1和d2?
发布于 2017-03-10 23:54:53
试试这个。
declare @rooms table
(
depa_key int,
room_key int,
d1 int,
d2 int
)
insert into @rooms(depa_key, room_key, d1, d2)
select 1, null, null, null
union all
select 1, 1, 1, 1
union all
select 1, 1, 1, 1
union all
select 2, null, null, null
union all
select 2, 1, 5, 3
union all
select 2, 1, 7, 2
union all
select 3, null, null, null
union all
select 3, 1, 6, 9
union all
select 3, 1, 5, 8
UPDATE @rooms
SET d1 = a.d1, d2 = a.d2
FROM (
SELECT depa_key, SUM(D1)d1, SUM(d2) d2
FROM @rooms
GROUP BY depa_key
) a
JOIN @rooms r ON
a.depa_key = r.depa_key
WHERE r.room_key IS NULL
SELECT *
FROM @rooms发布于 2017-03-11 01:58:53
使用CTE的解决方案看起来更具可读性。首先,我们获取depa_key的聚合信息,只获取room_key IS NOT NULL所在房间的记录。然后,我们通过该聚合数据更新room_key IS NULL所在的行。
;WITH DepaStats AS
(
SELECT
depa_key AS depa_key,
SUM(d1) AS sum_d1,
SUM(d2) AS sum_d2
FROM @rooms
WHERE room_key IS NOT NULL
GROUP BY depa_key
)
UPDATE R
SET
d1 = S.sum_d1,
d2 = S.sum_d2
FROM @rooms R
LEFT JOIN DepaStats S
ON S.depa_key = R.depa_key
WHERE R.room_key IS NULLhttps://stackoverflow.com/questions/42722351
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