我想要做的是查找与某个id匹配并按名称排序的所有记录。数据看起来像这样:
{
type:"receiving",
saleName:"Harshitha",
penId:"7aac88118420858d62f5ea55e22"
}
{
type:"receiving",
saleName:"Tom",
penId:"81fb1a79526f4e2bdc77aa7d73d"
}
{
type:"receiving",
saleName:"James",
penId:"81fb1a79526f4e2bdc77aa7d73d"
}我想要获取具有按saleName排序的特定penID的文档。例如:-我想获取具有此penId‘81fb1a79526f4e2bdc77aa7d73d’的文档,并按saleName对它们进行排序。像这样的顺序:
{
type:"receiving",
saleName:"James",
penId:"81fb1a79526f4e2bdc77aa7d73d"
}
{
type:"receiving",
saleName:"Tom",
penId:"81fb1a79526f4e2bdc77aa7d73d"
}我这样的看法,
View view = database.getView("receiving_view");
if (view.getMap() == null) {
view.setMap(new Mapper() {
@Override
public void map(Map<String, Object> document, Emitter emitter) {
if (document.get("type").equals("receiving") ) {
List<Object> keys = new ArrayList<Object>();
keys.add(document.get("penId"));
keys.add(document.get("saleName"));
emitter.emit(keys, document);
}
}
}, "1.1");
}
return view;然后我试着得到这样的数据,
View view = getView("receiving_view");
Query query = view.createQuery();
List<Object> keys = new ArrayList<Object>();
keys.add("81fb1a79526f4e2bdc77aa7d73d");
List<Object> allKeys = new ArrayList<Object>();
allKeys.add(keys);
query.setKeys(allKeys);
query.run();它不工作是因为我传递了一个键,但它们是视图…中的两个键但我不能将‘saleName’作为键传递,因为我只想按‘saleName’排序。做这件事最好的方法是什么?
发布于 2018-02-27 20:59:22
最后我找到了解决方案。我不想在这里使用setKeys,我应该使用键的范围,而不是一组特定的键。
我将startKey设置为[penID],将endKey设置为[penID, {}]。空映射在任何其他值之后进行排序,因此此键范围包括所有以penID开头的键。我改变了我的数据获取方法。这是它看起来的样子,
View view = getView("receiving_view");
Query query = view.createQuery();
query.setStartKey(Arrays.asList("81fb1a79526f4e2bdc77aa7d73d"));
query.setEndKey(Arrays.asList("81fb1a79526f4e2bdc77aa7d73d", new HashMap<String, Object>()));
query.run();https://stackoverflow.com/questions/48987965
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