引用中包含变量的Python列表

Question

我已经将我的列表编号为layer1，layer2 ...我想在调用时使用一个变量( playery )作为列表名称中的编号，因此如果playery等于4，则寻址的列表将为layer4

layer1 = [".", ".", ".", ".", "."]
layer2 = [".", ".", ".", ".", "."]
layer3 = [".", ".", "■", ".", "."]
layer4 = [".", ".", ".", ".", "."]
layer5 = [".", ".", ".", ".", "."]
playerx = (3)
playery = (4)
(layer(playery - 1))[playerx-1]= (".")

(layer(playery))[playerx-1]= ("■")

这就是我目前所拥有的，但它不能工作

Answer 1

这就是你应该做的。

layers = [[".", ".", ".", ".", "."],
          [".", ".", ".", ".", "."],
          [".", ".", "■", ".", "."],
          [".", ".", ".", ".", "."],
          [".", ".", ".", ".", "."]]

>> playerx = 3
>> playery = 4
>> layers[playery - 1][playerx - 1]= "."
>> layers[playery][playerx - 1]= "."

Answer 2

创建2D数组，如下所示：

layers= [layer1, layer2, layer3, layer4, layer5]

如果你想得到“”，你应该输入：

layers[2][2]