获取数据库中item_type的值，并在选项中将其选中

Question

我的刀锋上有这个：

<select class="form-control" id="item_type" name="item_type">
   <option value="physical-goods" <?php if ($product->item_type="physical-goods") echo 'selected=" selected"'; ?>>Physical Goods</option>
   <option value="digital-downloads" <?php if ($product->item_type="digital-downloads") echo 'selected=" selected"'; ?>>Digital Downloads</option>
   <option value="credits" <?php if ($product->item_type="credits") echo 'selected=" selected"'; ?>>Credits</option>
</select>

这就是它看起来的样子

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即使样本产品是实物商品，它也应该是

​

​

我的代码出了什么问题？

Answer 1

使用双精度等于单个==的instaed

<?php if ($product->item_type`enter code here`=="digital-downloads") echo 'selected=" selected"'; ?>

<select class="form-control" id="item_type" name="item_type">
   <option value="physical-goods" <?php if ($product->item_type=="physical-goods") echo 'selected=" selected"'; ?>>Physical Goods</option>
   <option value="digital-downloads" <?php if ($product->item_type=="digital-downloads") echo 'selected=" selected"'; ?>>Digital Downloads</option>
   <option value="credits" <?php if ($product->item_type=="credits") echo 'selected=" selected"'; ?>>Credits</option>
</select>