嗨,如果有人能帮助我,这将是伟大的。我用d3.js做了一个缩放平移,它工作得很好:
function zoom() {
var e = d3.event
var scale = d3.event.scale;
canvas.save();
canvas.clearRect(0, 0, width, height);
canvas.beginPath();
canvas.translate(e.translate[0], e.translate[1]);
canvas.scale(scale, scale);
draw();
canvas.restore();
}然后我想让图像只在画布区域内,我这样做了:
function zoom() {
var scale = d3.event.scale;
var e = d3.event,
tx = Math.min(0, Math.max(e.translate[0], width - imgBG.width * e.scale)),
ty = Math.min(0, Math.max(e.translate[1], height - imgBG.height * e.scale))
canvas.save();
canvas.clearRect(0, 0, width, height);
canvas.beginPath();
canvas.translate(tx, ty);
canvas.scale(scale, scale);
draw();
canvas.restore();
}下面是一个工作代码:https://jsfiddle.net/ux7gbedj/
问题是:例如,当小提琴被加载时,我开始从左向右拖动,比如说2次,图像没有移动,这很好,但是当我尝试从右向左拖动时,我必须至少拖动3次才能再次开始移动,所以我认为我做的事情不是很正确。
发布于 2016-09-27 04:13:17
你需要将受限的平移坐标(tx,ty)反馈给缩放行为对象,否则d3.event平移坐标是无界的,最终你会发现图像在一个角/边。也就是说,你将试图用你的最小/最大值限制图像拖动到一个-200
取自http://bl.ocks.org/mbostock/4987520的逻辑
...
// declare the zoom behaviour separately so you can reference it later
var zoomObj = d3.behavior.zoom().scaleExtent([1, 8]).on("zoom", zoom);
var canvas = d3.select("canvas")
.attr("width", width)
.attr("height", height)
.call(zoomObj)
.node().getContext("2d");
function zoom() {
var scale = d3.event.scale;
var e = d3.event,
tx = Math.min (0, Math.max(e.translate[0], width - imgBG.width * e.scale)),
ty = Math.min(0, Math.max(e.translate[1], height - imgBG.height * e.scale));
zoomObj.translate( [tx,ty]); // THIS
canvas.save();
canvas.clearRect(0, 0, width, height);
canvas.beginPath();
canvas.translate(tx, ty);
canvas.scale(scale, scale);
draw();
canvas.restore();
}
...
https://stackoverflow.com/questions/39691239
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