Python流控制打破混乱

Question

我正在尝试理解一个复杂的流程控制，我无法开始工作，所以我简化了它，也不了解它的工作原理。

简化的流量控制是：

smurf = True
print('smurf status: ', smurf)
jackets = list(range(5))
print(jackets)

for j in jackets:
    print('la la la la', j, '\n')
    while smurf is True:
        print('jacket is :', j)
        if j == jackets[-3]:
            smurf = False
            break
            print('smurf is FALSIOOOO')
        j += 1
        print('smurf with jacket ',j-1, ' be ok')
print('END OF SMURFGATE') 

输出为：

smurf status:  True
[0, 1, 2, 3, 4]
la la la la 0 

jacket is : 0
smurf with jacket  0  be ok
jacket is : 1
smurf with jacket  1  be ok
jacket is : 2
la la la la 1 

la la la la 2 

la la la la 3 

la la la la 4 

END OF SMURFGATE

我认为会发生的(但没有发生)是，一旦j次迭代达到测试条件，while循环将停止，流控制将跳到脚本的最后一行，并输出'END of SMURFGATE‘。

所需输出：

smurf status:  True
[0, 1, 2, 3, 4]
la la la la 0 

jacket is : 0
smurf with jacket  0  be ok
la la la la 1
jacket is : 1
smurf with jacket  1  be ok
la la la la 2
jacket is : 2


END OF SMURFGATE

Answer 1

对于for -循环，您缺少了一个额外的中断，现在您只中断了while循环。试试这个：

smurf = True
print('smurf status: ', smurf)
jackets = list(range(5))
print(jackets)

for j in jackets:
    print('la la la la', j, '\n')
    while smurf is True:
        print('jacket is :', j)
        if j == jackets[-3]:
            smurf = False
            break
            print('smurf is FALSIOOOO')
        j += 1
        print('smurf with jacket ',j-1, ' be ok')
    break # To escape the for-loop
print('END OF SMURFGATE') 

输出：

smurf status:  True
[0, 1, 2, 3, 4]
la la la la 0 

jacket is : 0
smurf with jacket  0  be ok
jacket is : 1
smurf with jacket  1  be ok
jacket is : 2
END OF SMURFGATE