如何修复错误:基数为10的int()的文本无效：'Luck'？

Question

下面的代码是我的课程中使用的代码。此时，"if int(what_skill) <0 or int(what_skill) > 9:“行产生了上面的错误。我尝试将其更改为str()，但是这又产生了另一个错误。

def player()：

vigor = 1

endurance = 1

strength = 1

dexterity = 1

intelligence = 1

luck = 1
points = 25
while points !=0:
    what_skill = input("What skill would you like to add to? Vigor, Endurance, Strength, Dexterity, Intelligance, Luck? ")
    print(what_skill)
    add_points = int(input("You have " + str(points) + " points left. How many points from 1-9 would you like to add to " + str(what_skill) + "? "))


    if int(add_points) > 9:
        print("Too many points")
        print(add_points)
    else:
        if int(what_skill) < 0 or int(what_skill) > 9:
            print("invaid choice")
        else:
            update_skill = int(what_skill) + int(add_points)
            points = points - add_points

Answer 1

您看到错误的原因是因为这些行

int(what_skill)

在您的示例中，这等同于

int("luck")

这没有任何意义-我认为您正在尝试使用int(luck) --引用变量中的数字

我会把你的技能改成字典，并使用下面这样的东西：

stats = {
  "Luck": 1,
  "Vigor": 1,
  "Endurance": 1,
  "Strength": 1,
  "Dexterity": 1,
  "Intelligence" : 1
}

points = 25
while points >= 1:
    what_skill = input("What skill would you like to add to? Vigor, Endurance, Strength, Dexterity, Intelligance, Luck? ")
    add_points = int(input("You have " + str(points) + " points left. How many points from 1-9 would you like to add to " + str(what_skill) + "? "))

    if int(add_points) > 9:
        print("Too many points")
    else:
        if stats[what_skill] < 0 or stats[what_skill] > 9:
            print("invalid choice")
        else:
            update_skill = stats[what_skill] + int(add_points)
            points = points - add_points

Answer 2

您会收到此错误，因为what_skill是字符串类型，并且通过类型转换，您无法将单词转换为整数。int('abc')将导致与您面临的错误相同的错误。

如果你想引用你在一开始初始化的变量，使用字典代替，key是技能，值是各自的点。现在，您可以作为myDict[what_skill]访问这些点。到目前为止，使用字典是最有效的解决方案。