单击链接时URL编码的字符和未找到的页面

Question

我在使用Django 2.1时遇到以下错误：

Page not found (404)
Request Method: POST
Request URL:    http://localhost:8000/user-accounts/%5Eregister/
Using the URLconf defined in my_project.urls, Django tried these URL patterns, in this order:

admin/
user-accounts/ ^register/$ [name='register']
user-accounts/ ^login/$ [name='login']
user-accounts/ ^logout/$ [name='logout']
bank-accounts/
The current path, user-accounts/^register/, didn't match any of these.

当我点击我的base.html标题中的一个链接时，我在浏览器中得到了奇怪的url http://localhost:8000/user-accounts/%5Eregister/。base.html中的链接包括：

<li class="dropdown-header"><a href="{% url 'user-accounts:register' %}">Register</a></li>
<li class="dropdown-header"><a href="{% url 'user-accounts:login' %}">Login</a></li>

用户帐户应用程序urls.py：

from django.urls        import path
from django.contrib     import admin
from .                  import views

app_name = 'user-accounts'
urlpatterns = [
    path(r'^register/$', views.register, name='register'),
    path(r'^login/$', views.user_login, name='login'),
    path(r'^logout/$', views.user_logout, name='logout'),
]

项目urls.py：

from django.contrib import admin
from django.urls import path, include

from user_accounts.views import register

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', register),
    path(r'user-accounts/', include('user_accounts.urls')),
    path(r'bank-accounts/', include('bank_accounts.urls')),
]

Answer 1

Django的新(>=2.0) path()函数不支持正则表达式。这就是为什么从字面上看，^字符是放在URL前面的。

如果您想继续使用正则表达式，请使用re_path()函数。