使用Google Test测试C函数

Question

我正在尝试使用Google Test来测试一些C代码，但我正在苦苦挣扎。我真的不知道如何测试代码。我试过一些东西，但我不知道它是不是可以。有没有人能给我解释一下我做了什么以及如何测试开关部分？

这是我写的测试：

    TEST_F(MPS_Tests, Wai_for_discharging_of_several_rails) {


        MPS__tenPowerUpTrigger enTrigger = MPS__enGetPowerUpTrigger();
        EXPECT_EQ(enPowerUpTriggerFstp, enTrigger);
        MPS__vOnEnterStateAcPu1();
        EXPECT_EQ(MPS__enGetInternalState(enAC), enStateAcPu1);
        EXPECT_EQ(MPS__u16GetSmEvent(enAC), enStateAcPu1);

下面是经过测试的代码：

MPS__tenPowerUpTrigger MPS__enGetPowerUpTrigger(void)
{
    /* TODO: rework after startup trigger is considerd by design */
    return enPowerUpTriggerFstp;
}

/* Wait for discharging of several rails */
void MPS__vOnEnterStateAcPu1(void)
{
    MPS__tenPowerUpTrigger enTrigger = MPS__enGetPowerUpTrigger();
    MPS__vSetInternalState(enAC, enStateAcPu1);

    switch (enTrigger)
    {
    case enPowerUpTriggerFstp:
        MPS__vSetWait(enAC, u16Time_AC1ASU_t4);
        break;
    case enPowerUpTriggerWakeUp:
        MPS__vSetWait(enAC, MPS_TIMER_NOWAIT);
        break;
    case enPowerUpTriggerReset:
        MPS__vSetWait(enAC, u16Time_AC1CSU_t2);
        break;
    default:
        /* error handling */
        break;
    }
}

谢谢!

Answer 1

要涵盖switch中的所有选项，最简单的方法是将MPS__enGetPowerUpTrigger更改为以下内容：

MPS__tenPowerUpTrigger MPS__enGetPowerUpTrigger(void)
{
    const MPS__tenPowerUpTrigger return_values[3] = { 
      enPowerUpTriggerFstp,
      enPowerUpTriggerWakeUp,
      enPowerUpTriggerReset
    };
    static int idx = 0;

    MPS__tenPowerUpTrigger return_value = return_values[idx];
    idx += 1;
    if (idx >= 3) idx = 0;
    return return_value;
}

..。然后调用MPS__vOnEnterStateAcPu1 3次？