如何在UIView中表示SFSafariViewController

Question

我有一个自定义的UIView，它有一个按钮属性，我想添加一个动作来打开webview in-app。为此，我想使用SFSafariViewController。以下是我尝试实现这一点的方法。

import UIKit
import SafariServices

class CustomViewScreen: UIView, SFSafariViewControllerDelegate {

@IBAction func privacyNoteBtnAction(_ sender: UIButton) {
    if #available(iOS 9.0, *) {
        let urlString = "https://stackoverflow.com/"
        if let url = URL(string: urlString) {
            let vc = SFSafariViewController(url: url, entersReaderIfAvailable: true)
            vc.delegate = self
           UIApplication.shared.keyWindow?.rootViewController?.present(vc, animated: true, completion: nil)
        }
    } else {
        // Fallback on earlier versions
    }
}

func safariViewControllerDidFinish(_ controller: SFSafariViewController) { 
  controller .dismiss(animated: true, completion: nil) // also not able to trigger this method when i tap "Done"
}

我甚至不能正确地使用这种方式，因为我得到的是“谁的视图不在窗口层次结构中！”此外，在点击“完成”按钮后，我无法调用SFSafariViewControllerDelegate方法来关闭视图。当我在UIView中时，有没有想法给出动作，或者有什么想法将这个动作连接到我的主控制器上，以便正确地使用present方法？

Answer 1

像这样做，

@IBAction func privacyNoteBtnAction(_ sender: UIButton) {
   if #available(iOS 9.0, *) {
    let urlString = "https://stackoverflow.com/"
    if let url = URL(string: urlString) {
        let vc = SFSafariViewController(url: url, entersReaderIfAvailable: true)
        vc.delegate = self

       if var topController = UIApplication.shared.keyWindow?.rootViewController {
          while let presentedViewController = topController.presentedViewController {
              topController = presentedViewController
          }

          topController.present(vc, animated: true, completion: nil)
       }

    }
} else {
    // Fallback on earlier versions
}
}

Answer 2

import UIKit
import SafariServices

class ViewController: UIViewController {

    var safariVC = SFSafariViewController(url: URL(string: "https://apple.com")!)
    
    override func viewDidLoad() {
        super.viewDidLoad()
        addViewControllerAsChildViewController()
    }
    
    //firstVCIdentifier
    
    func addViewControllerAsChildViewController() {
        addChild(safariVC)
        self.view.addSubview(safariVC.view)
        safariVC.didMove(toParent: self)
        self.setUpConstraints()
    }
    
    func setUpConstraints() {
        self.safariVC.view.translatesAutoresizingMaskIntoConstraints = false
        self.safariVC.view.topAnchor.constraint(equalTo: self.view.safeAreaLayoutGuide.topAnchor, constant: 100).isActive = true
        self.safariVC.view.bottomAnchor.constraint(equalTo: self.view.safeAreaLayoutGuide.bottomAnchor, constant: -100).isActive = true
        self.safariVC.view.leadingAnchor.constraint(equalTo: self.view.safeAreaLayoutGuide.leadingAnchor, constant: 100).isActive = true
        self.safariVC.view.trailingAnchor.constraint(equalTo: self.view.safeAreaLayoutGuide.trailingAnchor, constant: -100).isActive = true
    }

}

​

​

Answer 3

我不这样认为。UIView不能显示视图控制器，因为它们是不同的。只能在视图控制器中显示视图控制器。

所以我建议你的视图只获取触摸事件，并委托给viewcontroller，告诉它呈现一个SFSafariViewController。如下所示：

// view.h
@protocol AccountBindingDelegate <NSObject>
- (void)jumpWebVC:(UIButton*)sender;
@end
@interface CustomRegisterView : UIView
@property (nonatomic, weak) id<AccountBindingDelegate> delegate;
@end

// view.m
[agreementBtn addTarget:self action:@selector(agreementBtnClick:) forControlEvents:UIControlEventTouchUpInside];

- (void)agreementBtnClick:(UIButton*)sender
{
    if (self.delegate && [self.delegate respondsToSelector:@selector(jumpWebVC:)]) {
        [self.delegate jumpWebVC:sender];
    }
}

// code in controller
@interface uiviewContrller ()<AccountBindingDelegate> 

@end

- (void)viewDidLoad {
    _registerView.delegate = self;
}

//tell viewcontroller to present
- (void)jumpWebVC:(UIButton*)sender
{
    PSMFWebVC *webVC = [PSMFWebVC new];
    [self.navigationController pushViewController:webVC animated:YES];
}

UIView不需要知道url，他只需要告诉视图控制器: uiview中的某个按钮已经被点击了。以防你的uivew有很多按钮，你的CustomViewScreen会很重，这是不好的。