如何用Fractal在Json中显示数组？

Question

我想要将带有数组的REST API数据保存到数据库，它的工作，所有的值都保存到表中，但当我想在json中查看结果时，我仍然得到错误。

这是我的错误

 "message": "Argument 1 passed to App\\Transformers\\NewLoanOfferTransformer::transform() must be an instance of App\\Model\\AntiAttrition, array given, called in /home/insko23/testing.insko.my/vendor/league/fractal/src/Scope.php on line 338",

我的控制器

​

 public function new_loan_offer(Request $request, AntiAttrition $antiattrition)
    {
         $new = array_map(null, $request->mo_id, $request->id_clrt,$request->TaskID,$request->ACID,$request->CustIDNo);

            foreach($new as $new) {
                $request                  = new AntiAttrition;
                $request->mo_id           = $new[0]; 
                $request->id_clrt         = $new[1];  
                $request->TaskID          = $new[2]; 
                $request->ACID            = $new[3]; 
                $request->CustIDNo        = $new[4]; 
                $request->save();
            }

        $response = fractal()
            ->item($new)
            ->transformWith(new NewLoanOfferTransformer)
            ->toArray();
        return response()->json($response,201);
    }

​

我的应用\Transformer

​

<?php

namespace App\Transformers;

use App\Model\AntiAttrition;
use App\Model\SettlementInfo;
use League\Fractal\TransformerAbstract;

class NewLoanOfferTransformer extends TransformerAbstract
{
	public function transform (AntiAttrition $antiattrition)
	{
		return[
			'id' => $antiattrition->id,
			'mo_id'=> $antiattrition->mo_id,
			'assign_by'=> $antiattrition->assigned_by,
			'id_clrt' => $antiattrition->id_clrt,
			'TaskID'=> $antiattrition->TaskID,
			'ACID'=> $antiattrition->ACID,
			'CustIDNo'=> $antiattrition->CustIDNo
		];
	}
}

​

我想以json格式显示结果，如下所示

​

{
    "data": [
        {
            "mo_id": "123",
            "id_clrt": "10000000049",
            "ACID": "123",
             .....
        },
        {
            "mo_id": "1234",
            "id_clrt": "10000000045",
            "ACID": "1235",
             .....
        },
        {
            "mo_id": "124",
            "id_clrt": "10000000044",
            "ACID": "1245",
             .....
        },
       ],
}

​

请帮我解决这个问题

Answer 1

在foreach循环中，避免对数组和要迭代的数组元素使用相同的名称，可以将foreach($new as $new)重命名为foreach($newArray as $new)，或对代码逻辑使用有意义的名称。此外，使用$new['mo_id']来引用数组的键，而不是使用$new[0]