我一直在寻找bash命令的batch-file解决方案。
for file in temp/*/*; do ... done假设我有一个结构:
script.bat
temp
---- A
---- fileToExclude1
-------- 0
------------ SomeFile1
------------ SomeFile2
-------- 1
------------ SomeFile3
-------- 2
------------ SomeFile4
---- B
---- fileToExclude2
-------- 0
------------ SomeFile5
-------- 1
------------ SomeFile6
------------ SomeFile7
------------ SomeFile8
------------ SomeFile9
...如何使用批处理脚本(或命令行)中的模拟命令来处理文件(SomeFile1、SomeFile2、...、SomeFile9)?
发布于 2020-02-13 17:36:45
根据Gerhard Barnard收到的as a comment建议,最终的解决方案是:
for /d %i in ("temp\*") do for /d %j in (%i\*) do for %k in (%j\*) do echo %khttps://stackoverflow.com/questions/60203252
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