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pytest-mock pathlib.Path.open
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Stack Overflow用户
提问于 2020-05-13 04:56:35
回答 1查看 894关注 0票数 2

我需要使用pytest-mock模拟pathlib.Path.open

真正的open_func会打开一个yaml-file。返回值是一个常规的dict。如何模拟Path.open来加载另一个名为test-config.yamlyaml-file

我的代码不能正常工作,因为conf只会变成一个str ("test_config.yaml")。它应该是一个dict

代码语言:javascript
复制
from pathlib import Path

import yaml


def open_func():
    with Path.open(Path("./config.yaml")) as f:
        return yaml.load(f, Loader=yaml.FullLoader)


def test_open_func(mocker):
    mocker.patch("pathlib.Path.open", mocker.mock_open(read_data="test_config.yaml"))
    conf = open_func()

    assert isinstance(conf, dict)

编辑:为了更贴近我的现实问题,我提供了以下代码。我有一个TryToMock类,它基本上接受两个文件作为输入。load_files方法只是加载这些文件(实际上是.yaml文件)并返回输出。这些.yaml文件实际上是一些配置文件。

在我的单元测试中,我将通过pytest的parametrize多次调用TryToMock。因此,我想通过fixture加载原始配置文件。然后,在运行load_files之前,我可以在各种测试中monkeypatch一些条目。

为了不再加载原始文件,我需要在TryToMock中模拟Path.open函数。我想要传递monkeypatched yaml文件(即以dict的形式)。困难在于我必须区分这两个文件。也就是说,我不能简单地模拟具有相同文件内容的Path.open函数。

代码语言:javascript
复制
# TryToMock.py

from pathlib import Path
import yaml

# In my current working folder, I have to .yaml files containing the following
# content for illustrative purpose:
#
# file1.yaml = {'name': 'test1', 'file_type': 'yaml'}
# file2.yaml = {'schema': 'test2', 'currencies': ['EUR', 'USD', 'JPY']}


class TryToMock:
    def __init__(self, file_to_mock_1, file_to_mock_2):
        self._file_to_mock_1 = file_to_mock_1
        self._file_to_mock_2 = file_to_mock_2

    def load_files(self):
        with Path.open(self._file_to_mock_1) as f:
            file1 = yaml.load(f, Loader=yaml.FullLoader)

        with Path.open(self._file_to_mock_2) as f:
            file2 = yaml.load(f, Loader=yaml.FullLoader)

        return file1, file2




# test_TryToMock.py

import os
from pathlib import Path

import pytest
import yaml

from tests import TryToMock


def yaml_files_for_test(yaml_content):
    names = {"file1.yaml": file1_content, "file2.yaml": file2_content}
    return os.path.join("./", names[os.path.basename(yaml_content)])


@pytest.fixture(scope="module")
def file1_content():
    with Path.open(Path("./file1.yaml")) as f:
        return yaml.load(f, Loader=yaml.FullLoader)


@pytest.fixture(scope="module")
def file2_content():
    with Path.open(Path("./file2.yaml")) as f:
        return yaml.load(f, Loader=yaml.FullLoader)


def test_try_to_mock(file1_content, file2_content, monkeypatch, mocker):
    file_1 = Path("./file1.yaml")
    file_2 = Path("./file2.yaml")

    m = TryToMock.TryToMock(file_to_mock_1=file_1, file_to_mock_2=file_2)

    # Change some items
    monkeypatch.setitem(file1_content, "file_type", "json")

    # Mocking - How does it work when I would like to use mock_open???
    # How should the lambda function look like?
    mocker.patch(
        "pathlib.Path.open",
        lambda x: mocker.mock_open(read_data=yaml_files_for_test(x)),
    )

    files = m.load_files()
    assert files[0]["file_type"] == "json"
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回答 1

Stack Overflow用户

回答已采纳

发布于 2020-05-13 14:17:52

您必须向mock_openread_data参数提供实际的文件内容。您可以只在测试中创建数据:

代码语言:javascript
复制
test_yaml = """
foo:
  bar:
    - VAR: "MyVar"
"""

def test_open_func(mocker):
    mocker.patch("pathlib.Path.open", mocker.mock_open(read_data=test_yaml))
    conf = open_func()
    assert conf == {'foo': {'bar': [{'VAR': 'MyVar'}]}}

或者,您可以从测试文件中读取数据:

代码语言:javascript
复制
def test_open_func(mocker):
    with open("my_fixture_path/test.yaml") as f:
        contents = f.read()
    mocker.patch("pathlib.Path.open", mocker.mock_open(read_data=contents))
    conf = open_func()
    assert isinstance(conf, dict)

还可以重写最后一个案例,将open调用中的path参数替换为您的测试路径:

代码语言:javascript
复制
def test_open_func(mocker):
    mocker.patch("pathlib.Path.open", lambda path: open("test.yaml"))
    conf = open_func()
    assert isinstance(conf, dict)

或者,如果您对不同的配置有不同的测试文件,则如下所示:

代码语言:javascript
复制
def yaml_path_for_test(yaml_path):
    names = {
        "config.yaml": "test.yaml",
        ...
    }
    return os.path.join(my_fixture_path, names[os.path.basename(yaml_path)])

def test_open_func3(mocker):
    mocker.patch("pathlib.Path.open", lambda path: open(yaml_path_for_test(path)))
    conf = open_func()
    assert isinstance(conf, dict)

这可能就是您想在测试代码中实现的目标。

更新:这与问题的第二部分(编辑后)有关。如果您有模块作用域的fixture来预加载fixture文件,如问题所示,您可以这样做:

代码语言:javascript
复制
def test_open_func(mocker, file1_content, file2_content):
    def yaml_files_for_test(path):
        contents = {"file1.yaml": file1_content,
                    "file2.yaml": file2_content}
        data = contents[os.path.basename(path)]
        mock = mocker.mock_open(read_data=yaml.dump(data))
        return mock.return_value

    mocker.patch("pathlib.Path.open", yaml_files_for_test)
    conf = open_func()
    assert isinstance(conf, dict)

或者,如果您不喜欢使用嵌套函数:

代码语言:javascript
复制
def yaml_files_for_test(path, mocker, content1, content2):
    contents = {"file1.yaml": content1,
                "file2.yaml": content2}
    data = contents[os.path.basename(path)]
    mock = mocker.mock_open(read_data=yaml.dump(data))
    return mock.return_value


def test_open_func5(mocker, file1_content, file2_content):
    mocker.patch("pathlib.Path.open",
                 lambda path: yaml_files_for_test(path, mocker,
                                                  file2_content, file2_content))
    conf = open_func()
    assert isinstance(conf, dict)
票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/61761758

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